Recent content by Shashank Holla

The intensity of the light coming through the slits is directly proportional to the width of the slit And intensity is proportional to the square of amplitude. So amplitude2 is proportional to width

I didnt quite get you

Okay, I think these equations are right, because my answers match with the options. 8g-T=8(a1+a) T-6g=6(a1-a) 10g-T=10(a2-a) T-4g=4(a2+a) On solving, I got a1=100/77=1.29ms-2 a2= 360/77=4.67ms-2 T=4800/77=6.23g ms-2 a=10/11 ms-2=g/11ms-2 Tension over the pulley A is 2T=12.46g N Thanks a lot...

So should I consider different tensions over the 3 pulleys? What will be the relation between them then?

Since the pulley's are massless, they won't have torques on them, right? And even though the pulleys have equal weights on both sides (10+4 and 6+8), they will move I think

Assuming the tension in the string over pulley B is T, then the tension in the string over the pulley A has to be 2T. Assuming the tension in the string over pulley C is T'. then the tension in the string over the pulley B has to be 2T'. Now 2T' has to be equal to 2T since it is the same string...

Homework Statement [/B] Which of the following is correct? 1. The acceleration of pulley B is g/11 downwards 2. The acc. of pulley C is g/11 upwards 3. Tension in string passing over pulley A is 12.46g N 4. Tension in string passing over pulley A is 10g N Homework Equations F=m.a[/B]The...