Recent content by shillist
-
S
Problem involving square / square root of a complex number
Thanks for the help!- shillist
- Post #6
- Forum: Precalculus Mathematics Homework Help
-
S
Problem involving square / square root of a complex number
So in my case: arg(z^{1/2})=\frac{1}{2}arg(z) Then if we take z^{1/2}=n+i and set the argument of each side equal, we have: arg(z^{1/2})=arg(n+i) \frac{1}{2}\frac{\pi}{3}=arctan(\frac{1}{n}) \frac{\pi}{6} = arctan(\frac{1}{n}) Taking the tangent of both sides...- shillist
- Post #4
- Forum: Precalculus Mathematics Homework Help
-
S
Problem involving square / square root of a complex number
Homework Statement z = (n + i)^{2} n is a positive real number, and arg(z) = \frac{\pi}{3} Find the value of n. The attempt at a solution I am reviewing old problem sets from years past, and came across this problem that appears pretty simple. I have my old answer as n=\sqrt{3}...- shillist
- Thread
- Complex Complex number Root Square Square root
- Replies: 5
- Forum: Precalculus Mathematics Homework Help