For problem one, I notified the professor and he said the guide is incorrect...the answer is 34. Now it all makes sense for that one!
For problem two, whoops >.<
I take it I only use V=Lambda*Period and f=1/Period if I am only given the period and I'm trying to discover Velocity or...
Sure thing
1. Sorry...slight mix up in answers, the sheet says .029 but I am getting .0029. 1 / 340 = .0029. Am I even doing the right formula for this?
2. OK, so it is 16. Why am I using V=Lambda x Period and not V=Lambda / Period?
I am studying for an upcoming test, and it is known that there are hiccups in our study guide. I am stuck on two problems.
Homework Statement
1. What is the frequency, in Hz, of a sound wave (v=340 m/s) with a wavelength of 10 m?
2. A series of ocean waves, each 8 m from crest to...
OK
I have figured it out, the book is wrong and it was verified by the professor :)
I inputted: (1/16f) + (1/8o) = .1875, then (1/.1875)= 5.33.They did not use a negative sign.Thank you! =)
I have no idea where 45 and 16 came from, sorry it was a long night :blushing:
I input (1/8o) + (1/-16i) = .0625f, then go (1/.0625f) and come out with 16.
Either I'm missing something big, or I haven't drank enough coffee this morning. I even plugged the numbers into this website...
OK, I believe I have it after running a search for it...it's actually not in the book :(Is the equation:
(1/Object Distance)+(1/Focal Length) = (1/image location)
(1/45) + (1/36) = .05; then (1/.05) = 5.999
This is it? I'm just making sure :)
I'm having difficulty understanding how to estimate the location of an image in a lens/mirror.
I tried understanding it by going off the books question/answer section:
"A spherical concave lens has a focal length of 16 cm, and an object is placed 8 cm from the lens." It says the answer is...