Recent content by shravan

see: 6!+1 is not a perfect and similarly for all other multiples of 3 . it is found that 3,6,9,12,15.. are not the values that m can take .see by substituting the values in m!+1.but no condition is mentioned in the sum.so u have to prove that this condition has to be imposed on m.and u are...

I had worked on this question.i thought that m! is perfectly divisible by 8because m!/8 is a trianguar no.for m! to be a multiple of 8 it has to be >or=4.but m cannot be a multiple of 3 .as u had proved m!+1is not a perfect square. in the question no such condition is provided .so how u prove...

sorry sorry i forgot mention that this how i worked .the question is to prove m!+1 is a perfect square if m is triangular.

{if n is the sum of the first a natural numbers then it is a triangular number}eg 6=1+2+3 {a is any integer }show that m!+1is a perfect square if and only if m!/8 is a triangular number.m!/8 is a triangular number.so m!=o(mod8) therefore m has to be minimum 4 and not a multiple of 3.

6 generals propose locking a safe with a number of different locks .each general will be given a key to certain of these locks .how many locks and keys are required and how many keys must each general possesses such that the lock will be opened only if 4 generals are present?

there is no proof for the saying that the orbit in which an electron is moving is an integral multiple of angular momentum? how did bohr guess that it is angular momentum ;why didnot he try other angular variables? my question is how he knew angular momentum without any proof.

i am sorry. i did not see what u wrote before but ur last line caught my attention. thanks for guidelines to type equations.

it can be an integer certainly not (unless it is not mentioned that x is complex).it can be proved .by solving we get x-1\i.further xi + 1\-1. if x is not complex the expression will never be integer . x has to be an complex which is raised to an odd no: (which is quiet easy to understand...

can anybody tell when work done is negative ? and when it is negative why it is?

no there is no relation between the angles.the relation given is not going to help much. I think I will be getting a method for that sum.however thank u

standard condition means 298k and 1atm.are u sure it is 200kpa

sin(a+b)/sin(a+c)=[ sin(2b)/sin(2c)]^(1/2) then prove tan^2a=tanbtanc I have reached till {tan(a)cos(b)+ sin(b)} * {sin(c)cos(c)}^(1/2)= {tan(a)cos(c)+sin(c)}* { sin(b) cos(b)}^(1/2)

a number n when factorised can be written as a^4*b^3*c^7.find number of perfect square which are factors of n.a,b,c are prime >2. I have no idea how to start? please help.

first Q is simple if d is even .2^d is 2^2n .even no: are {expressed in this form } ie 4^n if n is prime i.e. n>or=2 4^n is > or = 16. 4^n -1 is never a prime no. { eg 16-1=15} so n cannot be even.thus we can prove by indirect method.

sorry re question I am sorry my question was wrong .however I wanted to ask how to find the no: of perfect squares in 360 without factorizing. I am sorry for sending the wrong question.