How to calculate the number of prime factors of 360?

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The discussion focuses on calculating the number of prime factors of 360, specifically through prime factorization. The prime factorization of 360 is established as 360 = 23 × 32 × 5. From this factorization, it is concluded that the perfect-square factors of 360 are {1, 4, 9, 36}, totaling four perfect-square factors. The conversation also highlights the distinction between counting all prime factors and distinct prime factors.

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how to calculate the number of prime factors of 360? please give the method
 
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HINT: Factor the number. :)

P.S. And, no, I am not being glib!
 
As Tide said: start factoring. It's not that hard. I'll get you started:

360= 2(180)= 2(2)(90)= ...
surely you can do the rest yourself. Did you mean number of distinct prime factors or just number of prime factors (i.e. counting "2" more than once).
 
sorry re question

I am sorry my question was wrong .however I wanted to ask how to find the no: of perfect squares in 360 without factorizing. I am sorry for sending the wrong question.
 
That's a different question; prime factorization of 360 yields
360 = 2^3 3^2 5
and therefore the only perfect-square factors included are
{\{1,4,9,36\}}
from observing the prime factorization. There are only four perfect-square factors of 360.
(The "1" is trivial tho :redface:)

*Then again, I'll reply later when I'll write an explicitly mathematical way to calculate the quantity of perfect-square factors of 360-->without factorization, as you mentioned :smile:
 
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