As Tide said: start factoring. It's not that hard. I'll get you started:
360= 2(180)= 2(2)(90)= ...
surely you can do the rest yourself. Did you mean number of distinct prime factors or just number of prime factors (i.e. counting "2" more than once).
#4
shravan
16
0
sorry re question
I am sorry my question was wrong .however I wanted to ask how to find the no: of perfect squares in 360 without factorizing. I am sorry for sending the wrong question.
#5
bomba923
759
0
That's a different question; prime factorization of 360 yields
360 = 2^3 3^2 5
and therefore the only perfect-square factors included are
{\{1,4,9,36\}}
from observing the prime factorization. There are only four perfect-square factors of 360.
(The "1" is trivial tho )
*Then again, I'll reply later when I'll write an explicitly mathematical way to calculate the quantity of perfect-square factors of 360-->without factorization, as you mentioned
Are there known conditions under which a Markov Chain is also a Martingale? I know only that the only Random Walk that is a Martingale is the symmetric one, i.e., p= 1-p =1/2.