Recent content by Singdasorrow

ok so since i know the coefficient of static friction and the normal force of the block. Fs ≤ .566 x .430(-9.8). Fs ≤ -2.385 N

Ok, so since I'm going to treat them individually. I have 3 force diagrams (1 for each object) and have the sum of the forces acting on each one. I am tho confused how to relate them because i do know i can't exceed fs. so i need to find an acceleration that will allow me to do that, then a...

Homework Statement A block of mass M1 = .430 kg is initially at rest on a slab of mass M2 = .845 kg, and the slab is initially at rest on a level table. A string of negligible mass is connected to the slab, runs over a frictionless pulley on the edge of the table, and is attached to a hanging...

thank you so much! that made things so much easier for me <3

i made the initial velocity into a force. 24.4 m/s x 100kg =2440 N

Homework Statement A 100 kg bale of hay falls off a truck traveling along a level road at 24.4 m/s. It lands flat on the road and slides 100m before coming to rest. Assume the acceleration is constant, compute the coefficeient of kinetic friction between the road and the hay. Homework...

woot thank you very much for your help! I've figured it out to the end <3

oooo i have the x component of the normal force. so Ncos(X) = 2.25 m/s^2

the only force that i know for ƩFx is the acceleration times the mass bc friction is 0 the acceleration in the y direction should b 0 because there is no movement up or down

ƩFx = 2.25 m/s^2 times mass = mass x acceleration. It simplifies to 2.25 = a ƩFy = N (the normal force) x cos(X) - mass x gravity = mass times acceleration. I plugged in the acceleration i found from ƩFx, but i couldn't simplify it enough to solve it

the y component of the normal force then would be Normal force x sin(X) I'm not quite sure i understand how to get the force from the acceleration without knowing the mass of the vehicle. And yes ur note is correct

In the y direction we have Normal force and weight perpendicular to the group (weight times sinX) In the X direction we have just radial acceleration of the car, i cannot think of anything else I can relate the two because of neuton's second law that the sum of the forces = mass x...

my force diagram has the normal force perpendicular to the incline, the weight perpendicular to the ground, and going in a forward motion with friction in the opposite. The acceleration though is towards the center of the circle I split it into components of X and Y. Sum of the forces in the...

Homework Statement A circular automobile racetrack is banked at an angle X, to the horizontal, such that no friction between the road and tires are required when a car travels at 30.0 m/s. The radius of the track is 400m. What is the angle? The problem i have is setting up the problem. I...

I apologize i do not have a picture to show. 1. Homework Statement [/b] A block of mass 250g is at rest on an incline that makes an angle of 30 degrees to the horizontal. The coefficient of kinetic friction between the block and the plane is 0.10. The block is attached to a second block...