Recent content by sitting_duck

For ΔT=300 K Cv=0.0125 kJ/mol.K Atomic Mass= 0.03995 kg Mass=50 Kg ΔU = CvΔT ΔU=(0.0125*300)*(50/0.03995) ΔU=4639.367 kJ Is this a resonable estimate for the energy required to heat up 50 kg of this gas? Also will the energy needed to cool the gas be the same?

Thanks for the help. Ok, so I was using the incorrect equations for constant pressure. ΔU=CvΔT should give me an answer for the work done. The Cv here being the molar heat capacity, so this will give me a solution for the work input for each mole? To find the total work input can I just...

Homework Statement Argon is heated from T1 to T2. Assume ideal gas behaviour. Calculate the energy input. Assume a constant volume, mass and constant specific heat capacity. Pressure variable T1=523.15 K T2=823.15 K M= 0.03995 kg m=50 kg R=8.31 Cv=0.0125 kJ/(mol.K) Homework Equations...

If I think of it like a car tyre on the ground. The weight of the car, divided by the number of wheels, subsequently divided by the contact area of the tyres is equal to the pressure of the tyres. So the pressure inside the membrane is equal to the force divided by the area the force is being...

Yes 0.3 bar is the excess pressure over atmospheric. So what you are saying is that the external force plus atmospheric pressure is balancing the internal pressure. So how do I resolve the external force into a pressure? P=F/A, but which area? The total contact surface area or just the area at...

Is it possible to find a realistic solution, asuming the membrane is inelastic? This isn't really coursework problem, but part of a research project. Therefore I am looking for the best way to model this.

Homework Statement An inflatable membrane is filled with an ideal gas at a pressure of 0.3 bar gauge. The gas is at 40 deg C and the volume of the membrane is 100m^3. The membrane is constrained on all sides and bottom, and a force of F acts on the top of the membrane. The material the...

...and the exploded views, could only upload 3 files at a time.

Sorry I didn't really explain how it works. Hopefully these pictures explain it better then words. The first one is when the mech is open and the second when it's closed. The third the detail of the lever.

Thanks stewartcs, that will work for the calculations. On a slightly different question. Can I make these assumptions in my force diagram? (R is the resistance force caused by friction) F1x(45x10^-3)=F2 F2-R=N Or do I have to take torque into account, I'm trying to keep it as...

I am redesigning a bicycle wheel quick release lever for a design project. I am trying to put together a force diagram as part of the project and I need to know the average force someones hand could apply to the tip of the lever to calculate the force exerted on the locking mechanism. Could...