Recent content by Skippy

When I read it, I was thinking the place from where you fire the projectile from is flat and then there's a hill in front of it. (ie alpha and beta both measured from the x-axis) Sounds like you're saying alpha is the angle between the projectile and the hill, if that's the case then you just...

Looks like you need to find the maximum height the stone makes it to, for B) and C). Remember at the max height velocity = 0

What's the change in Internal energy for a cyclic process? What's the change in Internal energy for an isotherm? Both of those are givens, that you don't need to calculate. Then you should be able to see what the change in energy is for the line you're looking at. Area under the graph should...

Maybe I'm a little late to post this... but it sounded like you were wondering how light interacts with atoms and how atoms can create light, plus you said you were learning about photons. So I thought I might as well post some physics concepts for you. Though I'll just have to hope I don't...

Both the D are the same, since both waves travel the same distance (from where the rock hit to where you are). T(2) = T(1) + 1.4s. You can't directly solve for anything, but you can use the fact that D(1)=D(2) to combine the equations and then solve for T(1).

Not sure if you can do that or not. You should just be able to use D= V(c)*T(1) and D= V(s) * T(2) where you know T(2) is just 1.4s longer than T(1).

I don't understand what you did. "distance from rock hitting ground to 1.4s mark". And Dconcrete = 4000 * 1.4s seems wrong as well. 1.4s is the interval between the two sound waves and not the time it takes for the Wave to travel through the concrete. Actually, I think there's something...

That's really oddly worded. I think it's falling with a certain speed and is being pulled on by the planet's gravity. If it has a thrust of 25 kN then it'll actually accelerate away from the planet at -1.2 m/s^2, where the negative sign denotes going away from the planet. However, if it has...

The equation is V = a*t. You said a= -.0033. Also, you know you're traveling at 1.5m/s. So you want to know when your acceleration will get you to -1.5 m/s (so it will cancel out with the foward motion and you will stop).

No, assume the reef isn't there when you calculate how long it takes the tanker to stop. Then see how far it goes using the time you calculated. If D > 500 then it hits...

At what time does the tanker come to a stop? Use that time to see how far it went.

Hmm can't edit... oh well... Actually, after thinking about it, there are multiple reasons why the spin is always n/2. You can simply talk about spin values (lower case cursive L) with respect to the number of states a particle can be in ('m'). From that you can see one reason why all...

For 1), if the initial velocity was 0 the ball wouldn't go anywhere... Distance = V(initial) * T - .5 g T^2

Take it out to a few more decimal places and it should be good. For the third one since the car is moving at D(car)= (blah) and the cycle is moving at D(cycle)= (blah blah). Can you combine those equations to simply give something that says the cycle will catch up? Like D(cycle) = D(car) = etc?

I think that's a bit off as .06 in the D = Vsound * T equation will say it's 18 meters deep