Recent content by sky.flower1234

I was mainly just going off of how my book says to go from point B to point A and that Vab=Va-Vb. Plus using Kirchoff's rules I figured that I am going in the way of the current across a resistor so then my change in potential would be negative?

Hey! When I say total resistance I mean of all the resistance combined in the circuit to help me find I1+I2 (this is including both E1 and E2) I changed up my formula to say this: -(R2*(E1+E2/2R1+2R2) for the second part of the question I guess the ration of my currents would be -1:1? This...

So I calculated the total resistance for both emf to be 2R1+2R2, does this sound about right? I just figured that R2 was in series for both while the 2R1 on the top was in parallel with the 2R1 on the bottom?

Homework Statement Find potential difference Vab between points a and b on the figure. All resistances and emf’s are indicated, note the polarity of the batteries. What happens if the polarity of E1 is reversed (polarity of E2 kept the same) and both emfs are made equal? Homework Equations...

Eek sorry! forgot about epsilon nought. The fnal units is N/C! Thank you SO much! I really appreciate you!

units would be nC/m^2

sorry 9.98E10^11

so would my final answer be: (111nC/m^3)(1m)/((4)(pi)(epsilon-nought)) to yield the electric field as: 9.99E10^11?

Okay, so I integrated that and put in that lambda=kx^2 (since we know K I am assuming this is okay). I'm assuming that AB=1m? I got that the integral equals k(x)/((4)(pi)(epsilon-nought)) from 0 to AB which I would think would equal K/((4)(pi)(epsilon-nought)).

well in that case my K= 111 nC/m^3. So I have Q, of course I can integrate over the length of the rod using dr from 0 to 1, but I'm stuck. Where does k come in? I'm a little lost . I'm assuming that you meant to put QQ on the top instead of dQ? In that case I would taket he charge from A...

I set up my integral that q= the integral of kx^2 dx to get that q=(kx^3)/3 from A=0 to B=1. this means that k=3Q or k=111 nC (Do I convert to C?) Thanks for your reply :)

I did the math and I got that the electric field equals 9.99E2 (this is converting nC to C) what would my units be? C/m?

Homework Statement Here is the question: Thin rod AB has length l=100 cm and total charge q=37 nC that is distributed in such a way that its line density ? is proportional to the square of the distance from the end A, i.e. ?(x) =kx^2. Determine electric field E at the end A of the rod. ...