Recent content by skydiver

We have an online system where you input the answer and it says if it's correct or not. If it's correct you get the points. 2748510000000 m/s^2 is the answer and the system recognized it (ie it's correct) I was inputting the number as 2.748 x 10^12 and hence the system said incorrect answer...

Apparently the STUPID homework system does not recognize x 10^y format yet the only error it gives is incorrect answer.

Thanks, I double checked everything yet nothing seems to work. Even tried a negative sign in front of all possible answers.

Homework Statement What is the magnitude of the gravitational field at the surface of a neutron star whose mass is 1.80 times the mass of the Sun and whose radius is 9.3 km? Homework Equations g = GM/r2 The Attempt at a Solution G is ofcourse 6.67x10^-11 r^2 is 8.649x10^7 m...

Yes, thank you. I did notice that the difference in his pulling techniques. But I am worried - what if this question is asked in an exam. What will the correct answer be? I am assuming the top one in this case as T2 is increased it is added onto T1.

Please let me know if one has trouble watching the video. To summarize, a block of mass of 2kg is suspended with a massless string. Let's call that string the top string which will have tension T1 of approx 20N. Now there is another same kind of string attached to the bottom of the block and...

This is not a homework problem so I am ignoring the template. I was watching Walter Lewin's video lectures and this experiment he performs intrigues me. I have given it a thought for over an hour but have no answer as to which and why will that string break. I have uploaded the experiment...

Homework Statement A particle is traveling in a straight line at a constant speed of 24.5 m/s. Suddenly, a constant force of 14.3 N acts on it, bringing it to a stop in a distance of 52.9 m. a. Determine the time it takes for the particle to come to a stop. b. What is its mass? Homework...

Ahh...Thanks so much. Stupid signs...

Thanks for replying. Yes, the ball would be at 15m twice in flight. Hence from equation 3 is tried: 4.9t2 + 20t - 15 = 0 The solution is -4.728 and 0.647 none of which make sense to me or are even close to the answer.

Homework Statement A ball is launched vertically upward from ground level with initial speed of 20 m/s. 1. How long is the ball in air? 2. What is the greatest height reached by the ball. 3. How many seconds after launch is the ball 15m above the release point. (Air resistance is negligible)...