Newton's Laws, Force and Kinematics

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SUMMARY

The discussion focuses on solving a physics problem involving Newton's Laws, specifically the calculation of time and mass for a particle subjected to a constant force. The particle travels at a constant speed of 24.5 m/s and is brought to a stop by a force of 14.3 N over a distance of 52.9 m. The correct mass of the particle is determined to be 2.52 kg using the work-energy theorem, correcting an initial miscalculation that led to an incorrect mass of 3.311 kg. The participants emphasize the importance of correctly applying the equations of motion and understanding the relationship between force, mass, and acceleration.

PREREQUISITES
  • Understanding of Newton's Laws of Motion
  • Familiarity with kinematic equations
  • Knowledge of the work-energy theorem
  • Basic algebra for solving equations
NEXT STEPS
  • Study the work-energy theorem in detail
  • Practice problems involving Newton's Laws and kinematics
  • Learn how to derive mass from force and acceleration using F=ma
  • Explore advanced applications of kinematic equations in real-world scenarios
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Students studying physics, educators teaching Newton's Laws, and anyone looking to deepen their understanding of force, mass, and motion dynamics.

skydiver
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Homework Statement


A particle is traveling in a straight line at a constant speed of 24.5 m/s. Suddenly, a constant force of 14.3 N acts on it, bringing it to a stop in a distance of 52.9 m.

a. Determine the time it takes for the particle to come to a stop.

b. What is its mass?

Homework Equations



1. vx2 = v0x2 +2a[tex]\Delta[/tex]x

2. [tex]\Delta[/tex]x = v0t + 0.5at2

3. F=ma

The Attempt at a Solution



I know how to solve part a. I use equation 1 to find a which is 5.673 m/s^2
I use that value of a in equation 2 to find t which is 4.318 s
This is all correct.

I am having trouble with part b - to find mass.
The only equation I have to find mass is f=ma
F is 14.3N given, a as calculated is 4.318 which gives m as 3.311 kgs which is incorrect.
The correct answer is 2.52 kg

So I thought that for F=ma, F must be the resultant force of some sort.
So I subtracted 24.5-14.3 (which I am sure is not a correct step to do) gives me 10.2

And that divided by a (4.318) gives me m as 2.362 which is close but not correct.

Any other thoughts? Thanks so muchEDIT: Aarggghh.. stupid me
I am diving by t (4.318) instead of the a I found (5.673).
Can't believe I spent so much time on this stupid stupid mistake.
 
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Welcome to PF!

Hi skydiver! Welcome to PF! :smile:

I'm glad you've sorted it out! :biggrin:

Just for the record, there's another way of finding the mass …

just calculate the work done and then use the work-energy theorem … work done = change in energy. :wink:
 


tiny-tim said:
Hi skydiver! Welcome to PF! :smile:

I'm glad you've sorted it out! :biggrin:

Just for the record, there's another way of finding the mass …

just calculate the work done and then use the work-energy theorem … work done = change in energy. :wink:

The really beautiful thing is, that the first equation he posted:
[tex]v_f^2=v_0^2+2ad[/tex] is completely equivalent.
Multiplying by a factor of [tex]\tfrac{1}{2} m[/tex] provides:

[tex]\tfrac{1}{2} mv_f^2=\tfrac{1}{2} mv_0^2+Fd[/tex]

(The dot operator is included in the way the equation is defined, since the [tex]a[/tex] term refers to the acceleration in the direction of the distance traveled.)
 

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