because from times 1-3 seconds the line goes from 0 to -18, i did 1/2 the base (y axis time) plus the height of -18. this got -36.
time interval 3-4 seconds have a constant velocity of -18 m/s so i added -18 to the first -18 getting -36. then i found the are from 4-5 by multiplying 1/2 the...
i posted a pdf of the question sheet. you can see the graph on the second page. I'm fairly sure i found the area correctly, but wouldn't that give me the displacement? and i need distance... look at number 7 on the pdf. please :/
I need to know how to determine distance from a velocity time graph. The graph lines are all linear with changes in direction and slope, but no curves.
I've tried finding the area under the lines but that doesn't seem to be it...
thank you. turns out i was over complicating things. the velocity was constant for the points i was finding so it was as simple as finding the slope. T.T
I need help with a very general question. I was asked to find the instantaneous velocity of a position time graph at .5 seconds. i know to do this i need to create a line that is the tangent to that point. Here lie the problem... how on Earth do i make that line, and how do i measure the slope...