Recent content by slpnsldr

ok, I've figured out my displacement.. but I am still unclear about how to find the planes new angle somethign to do with the sine law?

Homework Statement The wind is blowing at 72km/h south relative to the earth, and a plane is traveling 320km/h (28 degrees south of west relative to the wind) directly above a city. give displacement from the city in 2h time Homework Equations Plane is P wind is W Earth is E...

I got it! Thanks so much guys, you've helped me sooooo much

Well cool! Thanks so much :) However! I have come across another problem in this evil evil question! Why, doesn't this equation work to figure out the distance the ball travels? \Deltay =Vi\Deltat + 1/2a(\Deltat)2 When put in what we know i get the answer 174.636

but this is a formula i can use, my question is answered.. I am just trying to understand it now haha

wow that works.. Vi=0.5a(t) I haven't taken calculus.. I haven't taken much actually, I'm taking some DL courses now to brush it all up, thought i was doing fine trying to teach myself until this question came up.. I'm afraid i still don't completely understand. How did we jump from...

lol oh man I`m so lost! I should take this moment to first of all thank you for your patience lol. and then pray it will last a bit longer! So, what I am trying to find is the initial velocity. the velocity of the ball as it leaves the hand of the pitcher. i now realize that the final...

lol oh man I`m so lost! I should take this moment to first of all thank you for your patience lol. and then pray it will last a bit longer! So, what I am trying to find is the initial velocity. the velocity of the ball as it leaves the hand of the pitcher. i now realize that the final...

so... 0=0(4.2s)+0.5(9.8)(4.2)2 =172.872

hmm, so i need to rearrange? vi=s/t+1/2at2?

Sorry dac! I think i do understand now.. but.. the question asks at what velocity did he throw the ball, so i still have to figure out the balls velocity as it moves up right? first though distance should be... s= vit + 1/2 at2 =0(4.2)+0.5(9.8)(4.2)^2 =86.436m ok, so now... i have the...

hmm i don't quite understand what you mean tiny tim... is s=∆y? i don't know the distance... and don't i need to know initial velocity to use the equation your suggesting.. sigh lol I am not very good at this :frown:

hmm i don't quite understand what you mean tiny tim... is s=∆y? i don't know the distance... and don't i need to know initial velocity to use the equation your suggesting.. sigh lol I am not very good at this :frown:

tiny tim, if i use the second equation, i need to know the initial velocity. unless, i split the balls motion in half, and calculate for [down], using 0 for Vi. Which means i would have to also cut delta time in half delta y= 0(4.2)+0.5(-9.8)(2.1) = -10.29m [down]

Homework Statement A pitcher throws a ball vertically upward and catches it at the same lever 4.2 seconds later. A) What velocity did the pitcher throw the ball? B) What distance did the ball travel? Homework Equations Vfy^2=Viy^2+2ay\Deltay \Deltay=Viy+0.5ay(\Deltat)^2 The...