Recent content by softball1394

Twice.

...anyone there?

Well it slows down, but only slightly. But I can't figure out how to show that in a formula...

Homework Statement A 7g bullet moving horizontally at 200 m/s strikes and passes through a 150 g tin can sitting on a post. Just after impact, the can has a horizontal speed of 180 cm/s. What the bullet's speed after leaving the can? ANSWER = 161 m/s Homework Equations 7g = .007 kg 150 g...

Anyone? I just need help on getting the problem started :/

Homework Statement A stone rests in a pail that is moved in a vertical circle of radius 60 cm. What is the least speed the stone must have as it rounds the top of the circle if it is to remain in contact with the pail? Answer: 2.4 m/s Homework Equations v= 2 pi r / t The Attempt at...

I think I've got it! V= 2 pi r / t V= 2 pi .25 / .5 V=1.57/.5 V=3.14 m/s r = .25, not 25, because it has to be in meters. and t = .5 because if it takes 1 second to make 2 revolutions, it must take .5 seconds to make one revolution. yay (:

Homework Statement A mass of 1.5 kg moves in a circle of radius 25 cm at 2 rev/s. Calcualte (a) the tangential velocity, (b) the acceleration, (c) the required centripetal force for the motion. Answers: A) 3.14 m/s B) 39.4 m/s^2 radially inward C) 59 N Homework Equations v=2piR/T...

anyone there? Part one: Fgcos(20) - Ff = ma 138.28N - Ff = 15 x .25m/s^2 138.28N - Ff = 3.75 -138.28 -138.28 -Ff=-134.53 Ff=134.53N (Hopefully this is correct?) Part 2: Ff = u Fn u = Ff / Fn u = 134.53N / 138.28N u = .97 But the answer should be .65. What am I doing...

Homework Statement A horizontal force of 200 n is required to cause a 15 kg block to slide up a 20degree incline with acceleration of 25 cm/s^2. Find the friction force on the block and the coefficient of friction. ANSWERS: Friction force = 134N Coefficient of Friction = 0.65 Homework...

so would it be... f = m x a f = 2 x 3 f = 6 (a) f= m x a 6= 1 x a a = 6 (b) f= m x a 6= 4 x a a= 1.5 (c) f= 6N Oh, wow. That was a lot easier than I thought ahah. Thanks!

I'm pretty sure it's Newton's second law.

1. A force acts on a 2 kg mass and gives it an acceleration of 3 m/s^2. What acceleration is produced by the same force when acting on a mass of (a) 1 kg? (b) 4 kg? (c) How large is the force? Answers: (a) 6 m/s^2 (b) 1.5 m/s^2 (c) 6 N 2. - 3. I can't figure out what formula to...