Recent content by SolidSnake
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Prove the work done by F is zero for a curve on a sphere
Thanks for the help. Good night :)- SolidSnake
- Post #15
- Forum: Calculus and Beyond Homework Help
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Prove the work done by F is zero for a curve on a sphere
Well the work done by F would be zero then since it doesn't effect the "particle" when moving from point a on the curve to point b. I now understand it intuitively. Thank you :) How would i go about proving this though. Would i need to parametrize a curve along the sphere and show that it is...- SolidSnake
- Post #13
- Forum: Calculus and Beyond Homework Help
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Prove the work done by F is zero for a curve on a sphere
Well if the force is perpendicular at one point on the surface curve, and the surface is sphere wouldn't the force always be perpendicular to the curve regardless of which curve is chosen.- SolidSnake
- Post #11
- Forum: Calculus and Beyond Homework Help
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Prove the work done by F is zero for a curve on a sphere
The force would be going straight outwards, wouldn't it? with the length modified by f(x,y,z). which would mean it was perpendicular to the curve right?- SolidSnake
- Post #9
- Forum: Calculus and Beyond Homework Help
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Prove the work done by F is zero for a curve on a sphere
At any point the force would be the vector (f(x,y,z)x , f(x,y,z)y, f(x,y,z)z). Hmm the light bulb still hasn't gone on :(- SolidSnake
- Post #7
- Forum: Calculus and Beyond Homework Help
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Prove the work done by F is zero for a curve on a sphere
Doesn't that depend on the function f(x,y,z) ? since the force field will change depending on what that function is.- SolidSnake
- Post #5
- Forum: Calculus and Beyond Homework Help
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Prove the work done by F is zero for a curve on a sphere
We've yet to learn Stokes Theorem, though we have learned Green's theorem. But I don't see how Green's theorem would apply here as it is just a specific case of Stokes Theorem for two dimension (correct?).- SolidSnake
- Post #3
- Forum: Calculus and Beyond Homework Help
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Prove the work done by F is zero for a curve on a sphere
Homework Statement Prove that if an object moves along any smooth simple curve C that lies on the sphere x^2 + y^2 + z^2 = a^2 in the force field F(x,y,z) = f(x,y,z)(xi + yj +zk) where f is a continuous function, then the work done by F is zero. Homework Equations The Attempt at a...- SolidSnake
- Thread
- Curve Sphere Work Work done Zero
- Replies: 14
- Forum: Calculus and Beyond Homework Help
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Probability generating function (binomial distribution)
well i just realized that G(s) = E(s^{y}) = \sum \left(\stackrel{n}{y}\right)(sp)^{y}q^{n-y} is the same thing as (q + sp)^{n} . Also by definition p + q = 1 \Rightarrow q = 1-p which means... G(s) = E(s^{y}) = [(1-p) + ps]^{n}- SolidSnake
- Post #2
- Forum: Calculus and Beyond Homework Help
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Probability generating function (binomial distribution)
Homework Statement The probability generating funtion G is definied for random varibles whos range are \subset {0,1,2,3,...}. If Y is such a random variable we will call it a counting random varible. Its probabiltiy generating function is G(s) = E(s^{y}) for those s's such that E(|s|^{y})) <...- SolidSnake
- Thread
- Binomial distribution Distribution Function Probability
- Replies: 1
- Forum: Calculus and Beyond Homework Help
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Finding tangent lines to an ellipse that pass through a given point
then a point on the ellipse would be (x , root of (36 - x^2)/4 ) correct?. but even then wouldn't that leave me with the same problem when i set m = m- SolidSnake
- Post #3
- Forum: Calculus and Beyond Homework Help
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Finding tangent lines to an ellipse that pass through a given point
Homework Statement Find the equations of all the tangent lines to x^2 + 4y^2 = 36 that pass through the point (12,3) Homework Equations the derivative of the ellipse is dy/dx = -2x/8y (I'm not sure if that is correct, i have only recently learned implicit differentiation.) The...- SolidSnake
- Thread
- Ellipse Lines Point Tangent
- Replies: 3
- Forum: Calculus and Beyond Homework Help
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AM-GM Inequality: Prove 0 <= A <= B
:O the light bulb just went on. Thanks a lot :).- SolidSnake
- Post #5
- Forum: Precalculus Mathematics Homework Help
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AM-GM Inequality: Prove 0 <= A <= B
i added something i forgot to mention earlier. (B-A)^2 = B^2 -2ab + A^2 Assuming that (B-A)^2 = 0 And if i were to rearrange it i'd get B^2 +A^2 = 2ab And then if divided the 2 and took the root i'd be left with B+A/root 2 = root AB That root 2 is still throwing me off tho. :S- SolidSnake
- Post #3
- Forum: Precalculus Mathematics Homework Help
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AM-GM Inequality: Prove 0 <= A <= B
Homework Statement Show that: 0 <= A <= B A \leq \sqrt{AB} \leq (A + B)/ 2 \leq B Homework Equations root AB = geometric mean (A + B)/ 2 = arithmetic mean <= means less then or equal to.The Attempt at a Solution I managed to come up with something for the (A + B)/ 2 part. a < = (a+a)/2...- SolidSnake
- Thread
- Inequality
- Replies: 4
- Forum: Precalculus Mathematics Homework Help