Recent content by sophiebeth100

Ah I see, so ω=dθ/dt So to calculate the time, use time = distance / speed. Not 100% sure on this, but is the distance 0.1m? Since it is half the height of one side of the triangle? If that's right, time = 0.1/0.3 = 0.33s ω=dθ/dt ω=(π/6)/0.33 ω=π/2 rad/s Is this right?

Is that the change in β related to time? Where does time come into it?

The value stays the same?

I really can't find a relationship between those two things

Do you mean of CB and BA? But hmm are they the same?

I see. So when beta=30, the side CB is vertical. However, since CB=r, wouldn't the perpendicular velocity=0, since the machine only operates up and down?

I used the v for the hydraulic cylinder, 0.3, and the radius 0.2, as the edge of the triangle is. I think I have found my mistake - I had assumed B was the centre of the circular motion but I now see that B can move and this is wrong. Since there is no fixed point on the triangle, I don't know...

Could you be more specific in regards to my answer for a? Did I use the right formula? Is there a different formula I should be using?

Homework Statement Shown in picture Homework Equations So far just used w=v/r The Attempt at a Solution [/B] Could only do part a. W=v/r =0.3/0.2 =1.5rad/s For part b I would assume the velocity is zero? But I don't think that's correct. Any help with part b and c would be great, and is...

I wouldn't think there are any forces in the x-axis since the total force in the x-axis is zero. Does the force at GC act upwards? Equal to the total downward force, so 30kN?

Perhaps that GC is equal to 12kN? Not entirely sure if that's right but if so I could work from there.

Homework Statement The right triangles of the plane truss are all the same. What are the forces in members BH and HG? Diagram for question is below, or a link: http://puu.sh/nsw1k/aad8a8b134.png Homework Equations n/a The Attempt at a Solution Reaction force at A + reaction force at E...