Tangential acceleration is the radius times the angular acceleration, which we're trying to get to.
...you said the rope pulls up of the block with a force T and down on the pulley with T. Does that make Torque = 0?
So this rope exerts a force on the pulley. We're going to use the forces...
Hey Doc? Is linear acceleration the same as tangential acceleration? Because if we used all this to find the linear acceleration of the rope, maybe we could find the tangential acceleration of the pulley!
Okay there's the gravity pulling the block down, and there's the rope that's pulling upwards. (it's going down, but I mean the rope is resisting) Is it called tension?
ΣF = ma
ΣF = (4.20 kg)(9.81 m/s^2)
ΣF = 41.202 N
Now the rope pulls back up on the block again. I guess it would pull back up...
Heh. Okay, no lbs. Just Newtons. Newtons might add pounds, but that's only if you stuff them with figs.
Torque acts on the pulley.
Gravity and the moment of inertia act on the block.
ΣF = ma
Torque = I*alpha
We found the force ΣF = ma = 41.202 N of the block. That is the force that pulls on...
So...
You have to find the force of gravity on the block, then add it to the force the block exerts on the pulley.
4.20 kg x 9.81 m/s^2 = 41.202 N
Then to find the force exerted by the block on the pulley,
4.20 kg x lb rate = 9.25941501 lbs
9.25941501 lbs x 4.448 = 41.185878 N
41.185878 N x...
I'm having some trouble converting mass to force in this problem. Any help would be appreciated.
Homework Statement
The pulley shown in the illustration has a radius of 2.70 m and a moment of inertia of 39.0 kg*m^2. The hanging mass is 4.20 kg and it exerts a force tangent to the edge of...
Homework Statement
You accelerate your car from rest at a constant rate down a straight road and reach 22.0 m/s in 111s. The tires on your car have radius 0.320 m. Assuming the tires rotate in a counterclockwise direction, what is the angular acceleration of the tires?
Homework Equations...
Homework Statement
A computer hard drive disk with a diameter of 3.5 inches rotates at 7200 rpm. The “read head” is positioned exactly halfway from the axis of rotation to the outer edge of the disk. What is the tangential speed in m/s of a point on the disk under the read head...
Okay I just figured it out. Actually finding the circumferences did help.
I forgot to multiply the circumference of the track by the number of times the bike rotates around it. Once I multiplied the circumference of the track by 14 and did the math I had put together before, it worked...
Homework Statement
Your bicycle tires have a radius of 0.33 m. It takes you 850 seconds to ride 14 times counterclockwise around a circular track of radius 73 m at a constant speed. (a) What is the angular velocity of the bicycle around the track? (b) What is the magnitude of the angular...
Certainly. But she passes 0 two times. After that she only rotates for about 0.2 revolutions, right? Wouldn't that be the angular displacement instead?
-Tom