Recent content by speedskater

It turns out that 0.99m/s is right! Thanks everyone for all your help!

All they did was t=d/v, using 0.80m for d. Then they manipulated the formula d=((Vi + Vf)/2)t to find Vf, using 0.60 as d. They got the answer by fluke, because velocity and acceleration are always changing in a spring.

It's the Alberta high school physics textbook. It says 0.75m/s for sure. If all of you, who are experts in physics, agree with me and say it should be 0.99m/s, should I risk it and go with that answer? Or make up a way to get to 0.75m/s (as the rest of my class did) and just get partial points?

But if you do that (mass cancels, 1/2 cancels), you get 0.99m/s again!

Do you mean x2/xmax2? = .36/.64 = 0.5625? So 56% of the mechanical energy is potential energy? Which would mean that 44% is kinetic energy. Not sure if that's what you mean or not, or if I just did some completely useless calculations. If that's what you meant, I don't see how that will help me :/

Homework Statement A mass is oscillating on a spring with simple harmonic motion. Its amplitude is 0.80m and its maximum speed is 1.5m/s, at the point of equilibrium. What is the speed of the mass at 0.60m? Is there enough information to answer this question? The answer given is 0.75m/s...

Nope, I definitely haven't learned what you just did. If it helps, I think I'm supposed to assume it's moving in a straight line like a spring oscillating back and forth. The branch should be moving in a partial circular path, but those calculations would be more advanced than what I've been...

I don't know what angular frequency is :S We never learned anything like that. (Physics 20)

Homework Statement (Forgive me if I use certain terms wrong; I'm learning all of this in French) A branch at the top of a tree is swinging back and forth with a simple harmonic motion. Its amplitude is 0.80m. Its maximum speed at the point of equilibrium is 1.5m/s. What is the speed of the...