Recent content by spf
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High School Electromagnetic poles- repelling
Dear Rozy94, did you find out why your two electromagnets were always attracting each other? If yes, please tell us, it's really interesting! Thanks.- spf
- Post #6
- Forum: Electromagnetism
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Magnetic fields and charged particles
Yes. Yes. The reason for both is Maxwell-Faraday's law: a time-varying magnetic field creates an electric field. http://en.wikipedia.org/wiki/Maxwell_Laws#Faraday.27s_law http://en.wikipedia.org/wiki/Faraday%27s_law_of_induction#Maxwell.E2.80.93Faraday_equation- spf
- Post #2
- Forum: Introductory Physics Homework Help
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High School Electromagnetic poles- repelling
Another idea: did you check that both batteries are working correctly? If one of them didn't work, you would only have one electromagnet and one simple bolt, and they would behave exactly as you described: attract each other in each configuration. (They same applies if the wire is contacted...- spf
- Post #5
- Forum: Electromagnetism
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The number of lattice point in FCC?
Yes. If you like, just replace "atom" by "lattice point" everywhere in my previous post.- spf
- Post #4
- Forum: Materials and Chemical Engineering
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High School Electromagnetic poles- repelling
This is interesting... Have you tried out all the possibilities? Let's say magnet A has the ends A1 & A2 and magnet 2 has the ends B1 & B2. Did you try out ALL the following possibilities:"A1 to B1", "A1 to B2", "A2 to B1" and "A2 to B2" WITHOUT disconnecting the battery when turning the magnet...- spf
- Post #2
- Forum: Electromagnetism
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The number of lattice point in FCC?
Atoms on the sides are shared between two unit cells, so you can only count each one as 1/2 atom. Atoms on the edges are shared four unit cells, so they count as 1/4 atoms. Atoms on the corners are shared between eight unit cells, so they count as 1/8 atoms. Do the numbers add up now?- spf
- Post #2
- Forum: Materials and Chemical Engineering
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Solving a Graphite Structure Factor Calculation Problem
OK, up to now I tried many things to figure it out, have redone this calculation many times, rechecked the values and have tried out three different sets of coordinates of the A, B, A' and B' atoms in the unit cell and I always get the same result. I went the other way round by asking myself...- spf
- Post #2
- Forum: Advanced Physics Homework Help
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How to solve these equation?I try but getting wrong answer
Glad that I could help. Thanks to Ray Vickson for the elegant alternative substitution and to Karamata for the nice visual presentation of the solutions with wolfram-alpha.- spf
- Post #12
- Forum: Calculus and Beyond Homework Help
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Graduate Minority carriers in a Schottky diode
The electrons cannot flow from the metal to the valence band of the semiconductor because the valence band of the semiconductor is full. It's a n-type semiconductor, so it has an excess of electrons and thus electrons in the conduction band but no holes in the valence band. In case you meant...- spf
- Post #2
- Forum: Atomic and Condensed Matter
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A spring is compressed by 90 cm
The only difference to part 1 of the question is that now the speed of the block at the top of the hill is not 6 m/s but... how much?- spf
- Post #6
- Forum: Introductory Physics Homework Help
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Superposition of two wavefunctions
Glad to help.- spf
- Post #4
- Forum: Introductory Physics Homework Help
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Superposition of two wavefunctions
The following link should be helpful: http://en.wikipedia.org/wiki/Complex_number#Conjugation- spf
- Post #2
- Forum: Introductory Physics Homework Help
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A spring is compressed by 90 cm
At the beginning, the whole energy of the system is in the elastic energy of the spring. When the block is at the top of the hill, the energy is in the potential energy of the block and the kinetic energy of the block. Thus, it's NOT the potential energy which equals the sum of the elastic...- spf
- Post #2
- Forum: Introductory Physics Homework Help
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How to solve these equation?I try but getting wrong answer
Finding the two conditions for y/x is only the first step in solving the original equations. With this step you did not find the solutions to the original equations yet, you just narrowed them down. By now, you only know that the solutions to the original two equations satisfy either y=x or...- spf
- Post #9
- Forum: Calculus and Beyond Homework Help