Recent content by sphericow

Physics major yes, the paper is an electronic engineering paper too. I'm only my second year so I can't really take an educated stab at where my future will take me, but biophysics and medical physics seem very interesting.

Maybe if I give a more complete picture of my year, currently my papers are as follows: A Semester Quantum and Solid State Physics Relativity, Nuclear and Astrophysics Multivariable Calc Linear algebra B Semester Statistical and Thermal Physics Differential Equations...

They are all the 200 level (100 first year, 200 second year etc). The physics classes require diff-eq to be taken concurrently, in the previous calculus classes diff-eq were introduced and some simple methods/examples were introduced. EDIT: The statmech course uses this textbook...

All second year courses: Experimental Physics (Lab based with reports) Analog Electronics and Circuit Analysis (includes labs) Electricity and Magnetism Statistical and Thermal Physics Differential Equations Mathematical Modelling Anyone with experience with a similar course line up...

Thanks so for the help, I really appreciate it. My physical intuition seems to fly straight out the window when I'm analyzing circuits; so its really great to have someone confirm my reasoning.

So base current = 0. Then I1=I3=(6-.6)/10k. Since bass current = 0 the transistor must be off (cut off region).

Double post: Would Ib=0 since current takes path of least resistance? If so, transistor will be OFF and therefore Vce = 6v, since Ice = 0.

Thanks for the reply i really appreciate it. d. The diode will be forward biased e. This is my reasoning [PLAIN]http://dl.dropbox.com/u/14490370/currents.png IF that's correct how would I work out I2=Ib

Homework Statement [PLAIN]http://dl.dropbox.com/u/14490370/bjt.png Homework Equations beta=Ic/Ib By 'ON' I think the lecturer means the saturation region and by 'OFF' he means cut off. The Attempt at a Solution a. My reasoning is Ib= (Vs-Vbase...

I'm in first year and taking calc I (well the New Zealand equivalent), I have already covered most of the course at high school; differentiation rules, related rates etc etc etc. The only real difference is an introduction to some proofs and its generally deeper than what i received at high...