- #1

sphericow

- 12

- 0

## Homework Statement

[PLAIN]http://dl.dropbox.com/u/14490370/bjt.png

## Homework Equations

beta=I

_{c}/I

_{b}

By 'ON' I think the lecturer means the saturation region and by 'OFF' he means cut off.

## The Attempt at a Solution

a. My reasoning is I

_{b}= (V

_{s}-V

_{base emitter})/R

_{total}(6V-0.6V)/(20,000)=~ 270uAmps

b. Now if beta = 50 then I

_{c}=0.0135A

Therefore collector voltage = 6-(1000*.0135)=-7.5V - This can't be right so the bjt must be saturated instead. It follows that collector voltage = 0V.

Is this correct line of reasoning? It seems like I have answered part c so i can answer part b; or I'm completely wrong.

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