Recent content by SquidgyGuff

Is there anyway to do this without expressing u in terms of t? In the prevoud question I found the velocity transformation as follows:

Homework Statement The instantaneous force F acting on a particle, as measured in frame S, is Use the formula for the linear momentum () in and the definition of the acceleration a to show that The Attempt at a Solution The professor said that this required use of programs such...

I was hoping you wouldn't notice that, I was just too lazy to retype it into LaTex, but yes, it was included in my calculations (I appreciate your thoroughness though!)

So http://www.sciweavers.org/upload/Tex2Img_1442441349/eqn.png (by trig identities) and so the integral is http://www.sciweavers.org/upload/Tex2Img_1442441225/eqn.png

Oh and I misstated the equality above, it specifies that the div(curlA)=0 then it has continuous second-order derivatives.

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My first instinct was just to derive each of them with respect to t like such Is that right?

Homework Statement The problem puts forth and identity for me to prove: or . It says that I can use "straight-forward" calculation to solve this using the definition of nabla or I can use Gauss's and Stoke's Theorum on an example in which I have a solid 3D shape nearly cut in two by a curve...

Homework Statement A closed curve C is described by the following equations in a Cartesian coordinate system: where the parameter t runs monotonically from 0 to 2π, thus defining the direction of C. Calculate the area vector of the planar region enclosed by C, using the formula: 2. The...

Thank y'all so much! Just needed to make sure my reasoning was sound :)

Sorry about that last reply. Okay I get it now, so which is then equal to . So would that mean the the charge distribution is 0?

But when you take the gradient isn't it this? So taking the couble gradient would be: Or is the laplacian not strictly the double gradient? If there's no directionality then it does equal zero and there for the charge distribution on the plane is 0 and the field is 0 right?

Homework Statement Essentially it gives the potential above the xy-plane as and I am tasked with verifying it satisfies laplace's equation, determining the electric field, and describing the charge distribution on the plane. Homework Equations then The Attempt at a Solution As far as I...

If I looked at the charge distribution a point charge the field would look like this , but I know that isn't correct because I believe the total charge is zero. because half of the values of are negative and the other half are positive.