Recent content by ssar

  1. S

    Equivalent Resistance: 20ohms - Solving with a Circuit

    Yeah, it's just hard for me to see in the picture unless it's redrawn like Zryn did. That's just for me though.
  2. S

    Equivalent Resistance: 20ohms - Solving with a Circuit

    That last tip with the labeling each node thing is a nice tip for me. Thanks for that, I understand it better now. I just need to find some more circuits to practice on to see if I really have it.
  3. S

    Equivalent Resistance: 20ohms - Solving with a Circuit

    Yeah that makes sense. I just have trouble redrawing circuits. I need to work on that. Do you have any pointers or suggestions on how I need to approach it? Should I just imagine a current starting from A and redrawing it according to where the current branches off etc?
  4. S

    Equivalent Resistance: 20ohms - Solving with a Circuit

    Homework Statement This should be quite simple for most of you although I can't understand it. Circuit is attached below Homework Equations The Attempt at a Solution The answer is 20ohms, although I would have done R1+R3 + R4//R5 which would get 25ohms. The previous question was to find Rab...
  5. S

    Mechanics of solids question from my mid semester exam

    Oh ok, I kept confusing myself with it being a triangle or just being a rectangle. Thanks for the clarification.
  6. S

    Mechanics of solids question from my mid semester exam

    Ok well I know it has been a while but we just had a tutorial on this topic and did a similar question so here's my attempt. Here is the question http://yfrog.com/0fquestionzfj Wc = weight of concrete Ww = Weight of water Pc = force of concrete Pw = force of water Fw = stress of...
  7. S

    Mechanics of solids question from my mid semester exam

    Homework Statement A small dam of triangular shape as shown is made from concrete. Find the stresses on the foundation at A and B. Assume concrete and water weighs 25kN/m^3 and 10kN/m^3 (All dimensions in the attached picture are in metres) Homework Equations sigma = force/cross...
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