Equivalent Resistance: 20ohms - Solving with a Circuit

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Discussion Overview

The discussion revolves around determining the equivalent resistance in a circuit, specifically addressing a scenario where the expected answer is 20 ohms. Participants explore different methods of analyzing the circuit, including redrawing it for clarity and considering the paths of current flow.

Discussion Character

  • Homework-related
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant expresses confusion about how to arrive at the equivalent resistance of 20 ohms, suggesting an alternative method that results in 25 ohms.
  • Another participant questions the validity of their redrawn circuit, seeking confirmation from others.
  • A participant shares their approach to redrawing circuits by reducing lengthy wires and grouping resistors to clarify their arrangement.
  • One contributor suggests using color coding for nodes to aid in redrawing circuits and ensuring correct connections.
  • Another participant notes that certain resistors (R2, R4, and R5) can be ignored in the analysis because they do not affect the current path from point "a" to "d".
  • A later reply provides a visual link to clarify why some resistors do not influence the current flow, emphasizing the importance of the redrawn circuit.

Areas of Agreement / Disagreement

Participants exhibit a mix of agreement and disagreement regarding the methods of analyzing the circuit. While some find the redrawn circuit helpful, others remain uncertain about the implications of ignoring certain resistors. The discussion does not reach a consensus on the best approach to determine the equivalent resistance.

Contextual Notes

Participants express varying levels of understanding regarding circuit analysis techniques, particularly in identifying which resistors are relevant to the current path. There is an acknowledgment of the potential for confusion in circuit diagrams.

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Homework Statement


This should be quite simple for most of you although I can't understand it.
Circuit is attached below
R.JPG


Homework Equations


The Attempt at a Solution


The answer is 20ohms, although I would have done R1+R3 + R4//R5 which would get 25ohms.
The previous question was to find Rab and Rab = 25ohms.

How do i view the circuit to get 20ohms? I'm aware it would just be R1+R3, but why can't you do it my way?
 
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Do you agree with the way I have redrawn the circuit?
 

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  • R redrawn.jpg
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Yeah that makes sense. I just have trouble redrawing circuits. I need to work on that. Do you have any pointers or suggestions on how I need to approach it?

Should I just imagine a current starting from A and redrawing it according to where the current branches off etc?
 
My approach to redraw a circuit is to simply reduce the lengthy wires (because they have zero resistance) and bring resistors together as close as possible. Now it should be more clear to see whether the resistors are in parallel or series.
As Zryn has redrawn the circuit, it will quickly indicate you that R4 and R5 are parallel. Find equivalent resistance of R4 and R5 and add it with R1 and R3.
 
Keep in mind that circuits that test your knowledge of how resistors can be combined will be drawn in such a fashion as to confuse you.

If you have some time, you can practice redrawing them by getting several different color pencil/pen/highlighter/crayon/whatever and color over each different node in a different color, then redraw the circuit in a linear fashion from top to bottom or left to right so that all the resistors point the same direction, and double check that each resistor is connected to the right color nodes.
 
That last tip with the labeling each node thing is a nice tip for me. Thanks for that, I understand it better now. I just need to find some more circuits to practice on to see if I really have it.
 
In this circuit, the path of current goes from "a" through R1 and R3, to "d".

R2 goes nowhere, so you can ignore it.

Although R4 and R5 are certainly in parallel, they are not in the path of the current from "a" to "d".
They are shorted out by the wire going from R3 to "d".
So you can ignore them too.
 
Yeah, it's just hard for me to see in the picture unless it's redrawn like Zryn did. That's just for me though.
 
[PLAIN]http://dl.dropbox.com/u/4222062/series%20R2.PNG

Maybe this will make it clearer why R2, R4 and R5 are not involved. You could remove all of them without having any effect on the current in the meter marked "A" in the diagram.

Current only flows in the parts marked in red.
 
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