Recent content by ssulun

I should have written the effect of k1 in the equation 1 as k1(x1+x2), not k1x1. Also, the k2 spring will pull m3 with k2x2 (to balance the forces on the k2 spring). So should I write the equation for x3 as: m_3\ddot{x_3}=f-k_2x_2 or should I write an overall system with (m1+m2+m3) and...

I have modified it as: m_1\ddot{x_1}=-b_1\dot{x_1}-k_1x_1-k_1x_2 m_2\ddot{x_2}=-b_2\dot{x_2}-k_1x_1-k_1x_2-k_2x_2 (m_1+m_2+m_3)\ddot{x_3}=f But still, x1 and x2 don't depend on f and that bothers me.

b1 and b2 are kinetic friction constants, and k1 spring is squeezed from both x1 and x2 so I can change those parts, but your work gave me new ideas, thank you.

Sorry, but it would be a violation of forum's rules. If you write your steps, then I can point out what went wrong. Don't let the letters confuse you, it's a basic equation system with two unknowns (S and f). If you have time, try to rest a little and then try again.

Choose an equation and determine a parameter (S or f) that you want to leave alone (which equation or parameter you choose doesn't matter). Say, you have chosen S in the first equation. Then, leave that parameter on the left side of that equation alone.(Manipulate equation 1 so that only S will...

Homework Statement See attachment. f(t) is the input force and b1 and b2 are kinetic friction constants. There is no static friction. Homework Equations ƩF = m \ddot{x} F_s=kx F_f=b\dot{x} Ff is the force from friction and Fs is the force from spring. The Attempt at a Solution...