Recent content by Stochastic13

Isn't is simply due to loss of kinetic energy i.e. the book is moving (rotating and translating) due to kinetic energy that friction opposes. Since friction is not a conservative force, the kinetic energy is lost and since the book is on the flat table there is not potential energy so when the...

Nevermind, I had to use a substitution x = R tan (theta)

I am reading through this physics book and have trouble understanding how they integrated one of the problems the conditions are Conditions: // ignoring the constant for simplicity r = √(x^2 + R^2) sin(θ) = R/√(x^2 + R^2) Integration: ∫ R/(x^2 + R^2)^3/2 dx and the result is...

Ok I'll try that as well, thanks.

Yeah, it's a pretty nasty problem, I don't know why they would include it in our book without explanation.

Thanks I'll give it a shot.

The original equation is: (1/3)(x^2(50 - x^2)^(3/2)) when I take out x^2 I get: (1/3)(x^2*x^3(50/x^2 -1)^(1/3)) and if u= 50/x^2 -1 then du = -100/x^3 which doesn't help P.S. Latex code that you are using doesn't work and it makes it real hard to understand what you mean, if you could just...

actually I'm stuck after factoring out x^2 because I get: 1/3 * (50/(x^2) - 1)^(3/2), but I don't know how to proceed.

For parts I tried u=x, dv=x(50-x^2)^(3/2) How would you do it with trig sub?

Oh, I see :) Very Nice, Thanks :)

Sorry, it's kinda hard to read, I still don't follow.

Homework Statement How do you integrate: 1/3(x^2(50 - x^2)^(3/2)) Homework Equations The Attempt at a Solution I tried by parts with no luck :(

Thank you.

No, I wasn't. How would you solve it without vectors?

Homework Statement Two cars start moving form the same place. One goes north at a rate of 50 mi/hr, while the other heads east at a rate of 30 mi/hr. At what rate is the distance between the two cars changing exactly two hours later? Homework Equations The Attempt at a Solution...