thanks, i think I've figured it out. i got Mw=1.3 kg
also, i doubt you remember this, but you were helping me with an explosion question i was having trouble with
https://www.physicsforums.com/showthread.php?t=456273
i got an answer but it's wrong. your help would be greatly greatly...
so I've been stirring & baking but this wrong answer is the best i could find:
0=m1v1x'+m2v2x'+m3v3x'
=0.2(1.4)cos0+0.3(0.9)cos80+m3(1.80cos@)
m3=-0.1816cos@
then plugged that value into the y momentum equation:
0=m1v1y'+m2v2y'+m3v3y'
=0+0.3(0.9)sin80+(-0.1816cos@)1.8sin@...
Homework Statement
A 50g bullet traveling horizontally at 200 m/s embeds itself in a much more massive wooden block initially at rest on a horizontal surface ( \muk = 0.10). The block then slides 1.2 m toward an ideal spring and collides with it. The block compresses the spring (k=600.0 N/m) a...
Homework Statement
A 63kg student stands on 34kg cart that is free to move in any direction. The cart and student are moving together with a velocity of 3.2 m/s [W]. The student then starts to walk so that her velocity is 1.8 m/s [25 degrees W of N] relative to the floor. Calculate the new...
not sure. are you suggesting something like px=m1v1x'+m2v2x'+m3v3x'? wouldn't i then have two variables m3 and its angle? can the conservation of energy formula be used to substitute m3 into that equation or is energy not conserved in the explosion? I'm in grade twelve, so i don't really...
well that's just it, i don't know where to begin. beyond the fact that momentum and energy is conserved, I'm at a loss with this one. i tried throwing together a momentum equation where 0=m1v1'+m2v2'+m3v3' just to see what came of it and got something like 305g which obviously isn't correct. do...
Homework Statement
[FONT="Garamond"][SIZE="4"]A small explosive charge is placed in a rubber block resting on a smooth (frictionless) surface. When the charge is detonated, the block breaks into three pieces. A 200-g piece travels at 1.4 m/s, and 300g piece travels at 0.90m/s. The third...