Recent content by Stuffy01

I GOT THE ANSWER FROM A FRIEND: (G/l^2)(M/2+sqrt(2)m) Can anyone help me work it out now that the answer is known?

Thanks. See any easy mistakes or did I go the wrong direction?

Associated work: Base equation: Gravitational field force = GMm/(l^2) I see three gravitational forces at work: Gm/l^2 on the y-axis Gm/l^2 on the x axis GM/((sqrt(2) times l)^2) Add all three so 2Gm/2l^2 + 2Gm/2l^2 + GM/2l^2 = (G(4m+M))/(2((l)^2))

Simple Gravitation - With Answer - Help me work the middle steps Homework Statement Three objects -- two of mass m and one of mass M -- are located at three corners of a square of edge length l as in Figure P13.23. Find the gravitational field g at the fourth corner due to these objects...