Recent content by SU403RUNFAST

That makes sense, thanks I can complete the question

Homework Statement So i have a function f(x)=x^2 that is periodic -a<x<a and need to sketch this function from -3a<x<a. I know how to find the Fourier coefficients though. Homework Equations f(x)=x^2 sketch it periodically The Attempt at a Solution I know that a function is only periodic...

Homework Statement The plane with surface charge sigma lies in x-z plane at y=0, parallel to it at y=a there is a grounded plane. What is the field just above the bottom plane, find the potential between the planes Homework Equations discontinuity E=sigma/epsilon, V=Qd/Aepsilon take the...

So i just resolved the problem a different way and at the end I got y=(x^2+y^2)c. These are more circles that are orthogonal

wait yeah but wouldn't when i simplifed using e^()=e^() +e^K wouldn't this k=0 add a 1 and mess up the solution...

Plotting y=c-2x alone gives lines through each circle through origin so that works if i ignore K, thanks for your immense help and clarifying my stupid questions

Little c is a number though, 0,-2,2,-4,4,etc, I am going to assume you mean C-C/2=K, so i did the same thing to simplify by raising e^ln(), are you sure you can just take an average randomly to get K or it doesn't matter since it doesn't show up, it only shows up as K. So do I pick random K...

why are you subtracting C-c... and where does division by 2i come from? There arent any irrational numbers... What the hell is C t and e.. i can't plot this with so many random constants

wait nvm i got it, but just to make sure can i just get rid of the big constant C's and then all is left is ln(y)=ln(c-2x)

Unless they cancel out, but i don't think they would have the same value because they are different constants

Yes I understood it, i have now obtained -ln(y)/2 + C = -ln(c-2x)/2 + C i think to plot I have to choose the parameter C, thanks

i guess its the same if you differentiate it without solving for c first

okay i am going to use your work and solve and see if it is perpendicular thanks, but i plotted the original solutions and they came out as circles,i rewrote them as (x-c/2)^2+y^2=(c/2)^2, i will check

Homework Statement you are given a family of curves, in this case i was given a bunch of circles x^2+y^2=cx, sketch these curves for c=0,2,4,6, both positive and negative, solve the equation for c and differentiate both sides with respect to x and solve for dy/dx. You obtain an ODE in the form...

I know, you guys are assuming i am trying to solve some problem the situation is that a photon is annhilated in the presence of a stationary electron, forming an electron positron pair along with the original electron. Y+e=e+e+e