Recent content by Sunil Simha

LaTeX support on Atom editor is pretty decent. You might want to check out plugins developed by the community. These include compilation, syntax-highlight, auto-completion, table of contents view, internal pdf viewer etc.

Thanks for the answer Stephen. There are a couple of other points that are nagging me. In estimating the variance of the bin counts, the constraint that the sum of all bin counts is constant never appears (or does it? Did I miss something?). How would the estimate of the variance change if we...

I am working on astrophysical data and I have a large number of redshift values of quasars. Now, each redshift estimate comes with its estimated standard error naturally. If I plot a histogram of these redshifts, I would expect the bins counts to also have some sort of uncertainty. I am unable...

All you need to do is get the equation for the speed of a longitudinal wave in solids. I think this http://mysite.du.edu/~jcalvert/waves/mechwave.htm may help :).

Yes that's right. Only if your boundary is a circle can you refer to a circle. You must use the equation of the boundary given. Here, for example, the boundaries were y=x2, y=0 and x=1.

Your answer is right for part (A) but not for part (b). In part (b), you are supposed to find \frac{\vec{s_2}-\vec{s_1}}{Δt}. You just have to subtract each component (i.e. like final x-initial x and final y- initial y) separately and then divide the resultant vector by t. Your answer should...

Isn't it supposed to be y from 0 to x2 and and x from 0 to 1 ? Alternatively, x from √y to 1 and y from 0 to 1.

Yup the answer is right. Stick to cartesian coordinates on this one. What are the limits on y (in terms of x) and x?

Hi sonic, You are supposed to find how the height of the shadow varies with time right? You know that the height depends on the distance of the person from the source. Just write down the relationship between the two and see how it varies with time.

Hi, The position of a particle is a vector right? √(52+1002) is the distance. Again, average velocity is a vector. Displacement is the vector difference of the final and initial positions.

Hi, What you've done is right. Go ahead with the problem.

Hey we are all rookies :smile: We get two equations right? -1.5= v_{0y}t + \frac{g}{2}t^2 23=v_{0x}t All we have to do is eliminate t. Moreover, v0x and v0y are related. So, you should be able to find v0x explicitly (and hence v0y). Could you check you answer again? I seem to be...

Hi, Isn't volume charge density simply -\nabla .\vec{P}? And since they have not mentioned \epsilon_r, you cannot use it in your solution. Moreover, they have not said that the material in linear, isotropic and homogeneous... so \vec{P} and \vec{E} may not be related as such.

Hi SlooM, Are you sure v0y is 0 in the first equation that you've used to find t?

There's nothing wrong with your approach. Why don't you go ahead with it?