Recent content by Sushmita

I typed it wrong. I meant uncertainity in momentum.

Oh yeah. I was totally missing this out. I tried the whole problem by calculating Δp from √(<p2> - <p>2) I am getting uncertainity in momentum too now which is Δp = πħ/L. So now (Δx)(Δp) = L × πħ/L = πħ = π× (h/2π) = h/2. But this is not the answer. Answer is (d) h/√3

Okay. i get it now. Thanks a lot.

But this is a one dimensional potention. There is no degeneracy.

Homework Statement For the ground state of a particle moving freely in a one-dimensional box 0≤x≤L with rigid reflecting end points, the uncertainity product (Δx)(Δp) is (A) h/2 (B) h√2 (C) >h/2 (D) h/√3Homework Equations The uncertainity principle says that - (Δx)(Δp) ≥ ħ/2 Ground state energy...

Homework Statement The ground state energy of 5 identical spin 1/2 particles which are subject to a one dimensional simple harkonic oscillator potential of frequency ω is (A) (15/2) ħω (B) (13/2) ħω (C) (1/2) ħω (D) 5ħω Homework Equations Energy of a simple harmonic oscillator potential is En...

I am attaching my solution in the attachment below.

Homework Statement [/B] A particle of mass 'm' is initially in a ground state of 1- D Harmonic oscillator potential V(x) = (1/2) kx2 . If the spring constant of the oscillator is suddenly doubled, then the probability of finding the particle in ground state of new potential will be? (A)...