Recent content by TeeBeeCee

Good guess. I just checked and the maximum pressure of the hydraulic pump is 300 bar.

I don’t suspect a mis-calibration. It’s just that torque specs are important. A loose bolt or nut can cause severe equipment damage. Just trying to make sure I limit my liability.

Was this chart generated from the data table I provided? If so, the point I made was that I have no idea if the data is correct and wanted to verify.

Currently, I use a table of pressure (measured in BAR, not PSI) provided by the vendor of the hydraulic tear down bench. Some torque specs are lower than listed, or are between the values. I need to be able to calculate the amount of hydraulic pressure needed to be able to tighten to any given...

It would be very helpful if you provide an example. I really don’t understand the formula you provided. Let’s say r=16”, beta=6 degrees, I’m lost after that. Sorry, as you can see math is not my strong suit.

Yes, once the ram breaks the nut or bolt loose, the hydraulic motor can remove a lot faster (decent rpm). It sacrifices power for speed. It does not play a part in the question.

From the diagram with the triangle, where is the torque variable? What is the formula to determine the torque given the variables listed?

I was thinking the same thing about getting measurements. I don’t have any drawings. I will reach out to the vendor to see if they will send any. In the meantime, I will try to get the best measurements I can. To get the angle of the ram, I used a digital inclination meter.

It’s been a while since I’ve done any trigonometry. In looking at your annotation, I understand what the variables are. X will change by 6”, the length of the stroke. The angle will also change. When the rod is fully retracted at the beginning of the stroke, the angle is 6 degrees. At the end of...

Here are the pictures and some additional information. The cylinder stroke is 6 inches. It takes 12 strokes to turn the drum 360 degrees, which is 30 degrees per stroke. At the beginning of the stroke the angle of the cog to the gears on the drum is about 6 degrees. At the end of the stroke it...

The hydraulic ram pushes the gear to generate the rotational force. I will post pictures and measure the stroke tomorrow. For the center to pivot radius, do you mean from the center of the gear to where the end of the ram meets the gear (Post #8 figure, variable r)?

No instrument to measure the torque. Isn’t pressure just one of the variables needed? In the example, 100 PSI of hydraulic pressure is applied to a piston area of 13 square inches, which will develop 1,300 ft pounds of force. In the formula T = F x r x sin(theta), it looks like to me like r will...

Building on variables needed to calculate a precise answer, the ram has a maximum stroke length, and as it extends to push the gear, the angle will change as the end of the gears travels in an arc per X degrees of gear rotation. What about the other components of the question? What other...

Please disregard this post if this forum is only academia related. This is a real word physics question. I work in a hydraulic cylinder repair shop. I have a hydraulic machine that can tighten and loosen bolts and nuts with a lot of torque. When tightening, it is important to know how many...