There must be a redistribution of charge if the surface of the conductor is to remain an equipotential. This induced polarization results in a potential that goes as 1/r4 (the usual dipole goes as 1/r2, plus an extra 1/r2 to account for the decreasing strength of the induced dipole with...
Well, I'm not British or American and I'm not a student, but I did stay at a Holiday Inn Express last night. I'm going to go with the AP exam. The questions are more difficult because they more thoroughly explore your knowledge of the subject.
Yeah, a similar thing happened with my wife. About a year after we started dating, she scored a really high-paying job and now I'm on easy street (left off of Monroe). The best part is that the money keeps coming. I haven't had to work a day all weekend.
Charge redistributes itself on the surface of the conductor in response to the presence of the charge. Negative charges are brought close to the positive charge, resulting in a net attraction.