Recent content by Tepictoc

Agreed. I did some testing and I would get the same μs on the angled surface test as in the horizontal test if I applied the force at 14 cm. That is μs = 0.32

Thanks a lot, that helps me. The equation "mg*L - μ*mg = 0" was what my teacher wrote down for me when he was trying to help. First we have mg*L - F*x = 0 and as mentioned earlier F = Ff = μ*N and N=mg that's how I got the "dead wrong equation". He was using it to separate μ.

Homework Statement I have a box on a horizontal plane. Given data: mass = 0.25kg height of object = 14 cm width of object = 9cm Calculate the coefficient of static friction. Homework Equations μs = Ff/N (N is the normalforce) F = Ff = μ*N mg = 2.45 Newton The Attempt at a...

L1(m1+m2) = m2L 10.3L1 = m2L 10.3L1/10.3 = 5.5*5/10.3 L1 = 2.6699 m L2 = 5-2.6699 L2 = 2.3301 m

m1L1 = m2L - m2L1 Moving all L1s to the left m1L1+m2L1 = m2L I don't know how to isolate L1. Do I divide both sides by m2?

L2 = L-L1 m1L1 = m2(L-L1) m1L1 = m2*L - m2*L1 m1L1 = m2L - m2L1

L2 = L-L1 4.8L1=5.5(L-L1) and then I'm not sure.

Simplifying 4.8L1 = 5.5(5-L2) 4.8L1 = (5 * 5.5-L2 * 5.5) 4.8L1 = (27.5-5.5L2) Solving 4.8L1 = 27.5 -5.5L2 Divide each side by 4.8. L = 5.729166667 -1.145833333L2 L1+L2 = 5 5.72-1.14L2 + L2 = 5

But the answer is correct? Also Thanks a lot everyone for your help!

I tried using the method to calculate a hanging weight held up by two strings but I realize that's completely wrong here. I tried solving it with algebra here as suggested: L1 = L-L2 m1*L-L2 = m2*L2 4.4*5-L2 = 5.5*L2 22-L2 = 5.5*L2

Is this correct? 22-L2 = 5.5*L2 22-L2-5.5L2 = 5.5L2-5.5L2 22-6.5L2 = 0 -6.5L2 = 22 6.5L2/6.5 = 22/6.5 L2 = 3.384 m which means 5-3.384 = 1.616 L1 = 1.6 m L2 = 3.3 m

I am pretty sure I understand what you mean but I get stuck after a while again. L1 = L-L2 m1*L-L2 = m2*L2 4.4*5-L2 = 5.5*L2 22-L2 = 5.5*L2

L1+L2 = 5m 4.8L1 = 5.5L2 L2 = 4.8L1 L1+4.8L1 = 5 Am i on the right path? I am not sure what to do next. Or is this another way to do it? L1*4.8 = L2*5.5 L1 = 0.872L2 0.872L2+0.872L2 = mg 1.744L2 = mg L2 = 5.5/1.744 = 3.15 L1 = 0.872*3.15 = 2.74 Actually then the total becomes too...

L = L1+L2 5 = L1 +L2 If I knew L1 then I would know what L2 is but how do I get L1? If L1 was 2m then L2 would obviously be 3m.

L1 < L2 The entire length of the seesaw is 5m. In the picture the pivot isn't at 2.5m, it's closer to L1. I don't understand the last part. Also sorry if I am confusing, English is not my first language.