Recent content by tex43

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    How Does Removing Ammonia Affect Chemical Equilibrium?

    Equilibrium If in the system, nitrogen, hydrogen and ammonia, at equilibrium you "remove" ammonia, the system reacts according to Le Chateliers Principle, which states that a dynamic equilibrium at equilibrium opposes any change imposed. Thus, more ammonia will be produced by reaction between...
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    How to use Beer-Lampert law without knowing pathlength?

    Hang on! I think I may have it! You just click "quote" right?
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    How to use Beer-Lampert law without knowing pathlength?

    Here's a dopy question - how do you get to display the originally posted questions when answering?
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    How to use Beer-Lampert law without knowing pathlength?

    Thanks Text, is there a way to create a calibration curve AFTER the analyses have been done? I already have my data in the form of FT-IR graphs, how can I create a calibration curve? Make solutions with a range of concentrations which include your estimated value and measure their...
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    How Does Decreasing Temperature Affect SO3 Production in a Chemical Equilibrium?

    Apologies Borek, didn't read the question properly ... cardinal sin.
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    How Does Decreasing Temperature Affect SO3 Production in a Chemical Equilibrium?

    Le Chateliers Principle states that any dynamic equilibruim will oppose changes imposed. Therefore heating an endothermic reaction will force the equilibrium in the endothermic direction which in your example would be to the right
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    Detailed electrochemistry question

    How pure are the Pt, Si and SiO? There may be side reactions?
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    How to use Beer-Lampert law without knowing pathlength?

    Without the path length the Beer-Lambert law is redundant. One way round your problem would be to construct a calibration curve for your substance vs absorbance and then simply read off your concentration at the appropriate absorption
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    Motion of electrons in orbitals and shape of orbitals

    "If you average over all possible magnetic quantum numbers, then the p-orbital is spherical". Surely for a p-orbital with an orbital angular momentum quantum number of 1 the wavefunction describes a dumbell shape. In order for the wavefunction to descibe a spherical orbital the orbital...
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    D-orbital Splitting: Coordination Compounds vs. Transition Metal Compounds

    Real bonds are classified in many ways, strength is one interaction is another etc. All bonds can be "thought of" as attraction between charges its how we describe that attraction that makes the difference. Clearly the attraction between two hydrogen atoms in a hydrogen molecule is different...
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    Will a Carbonate React with Carbonic Acid? A Chemical Reaction Explanation

    Carbonic acid doesn't exist in the free state. When CO2 dissoves in water an equilibrium is set up between CO2 molecules (possibly solvated) and water on one hand and an aquated proton (a hygrogen ion) and the aquated hydrogencarbonate ion on the other. The concentration of hydrogen ions is too...
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    D-orbital Splitting: Coordination Compounds vs. Transition Metal Compounds

    Quite right, d orbitals are split by any crystal field surrounding the central ion. My only input was to correct the statement that there was no fundamental difference between covalent, coordinate and ionic bonding.
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    D-orbital Splitting: Coordination Compounds vs. Transition Metal Compounds

    Yes. Ionic bonding exists between this ion as a whole and a positively charged cation. Bonding between the oxygen atoms and manganese is best described as multiple via overlap between 3d orbitals on manganese and hybrid sp3 orbitals on oxygen and is thus covalent. The negative charge arises...
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    D-orbital Splitting: Coordination Compounds vs. Transition Metal Compounds

    There is a fumdemental difference between covalent and coordinate bonding. In the former and electron pair is shared between two atoms due to large overlap of adjacent atomic orbitals and the bond is very strong in the order of 300 to 450 kj per mole, whereas in the latter minimal overlap occurs...
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