How Does Decreasing Temperature Affect SO3 Production in a Chemical Equilibrium?

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In the discussion regarding the equilibrium of the reaction 2SO3(g) <-> 2SO2(g) + O2(g) with an enthalpy change of H = 197 kJ, it is established that the reaction is endothermic. When the temperature decreases, according to Le Chatelier's Principle, the equilibrium will shift to counteract the change. Since the reaction absorbs heat, lowering the temperature will cause the equilibrium to shift to the left, resulting in an increase in the number of moles of SO3. The initial misunderstanding about the temperature change being a heating effect is clarified, emphasizing the importance of accurately interpreting the conditions affecting the equilibrium.
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What will happen to the number of moles of SO3 in equilibrium with SO2 and O2 in the reaction
2SO3(g) <-> 2SO2 (g) + O2 (g) H = 197kJ if the temperatrue is decreased?

I know this is endothermic, so heat is on the reactant side and that the reaction will shift to the left, so SO3 increases?
 
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Le Chateliers Principle states that any dynamic equilibruim will oppose changes imposed. Therefore heating an endothermic reaction will force the equilibrium in the endothermic direction which in your example would be to the right
 
tex43 said:
Le Chateliers Principle states that any dynamic equilibruim will oppose changes imposed. Therefore heating an endothermic reaction will force the equilibrium in the endothermic direction which in your example would be to the right

(bolding mine)

According to the original question temperature is decreasing. That means mixture was cooled, not heated.
 
Apologies Borek, didn't read the question properly ... cardinal sin.
 
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