Recent content by The Futur

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    What are the torque and power calculations for a belt drive system?

    how do i convert taht to rev/min. i tryed 62.8/(2pi/60) and i got some weird answer
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    What is the kinetic energy of a falling rock?

    so it will be v = √(2gx) v = √(2(9.8)100) v= 44.27m/s ? and no i don't know how to calculate the second part
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    What are the torque and power calculations for a belt drive system?

    So Va=RaxWb = Vb=RbxWb Since Va=7.85m/s Vb=RbxWb 7.85=0.125xWb 0.125Wb=7.85 Wb=7.85/0.125=62.8rev/min is that correct?
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    What is the kinetic energy of a falling rock?

    Homework Statement b) A person standing on the edge of a 100 m high cliff drops a 0.5 kg stone vertically downwards. Determine the final velocity of the stone after falling 100m, and its kinetic energy. Homework Equations Final velocity v = √(2gx) The Attempt at a Solution final...
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    What are the torque and power calculations for a belt drive system?

    yeah i do know it's 300rev/min, but how did u find the 300rev/min? so to answer the question. Q. The rotational speed of pully B A. Since pully A as a rotational speed of 300rev/min and both pully have the same linear speed, so pully b as a rotational speed of 300rev/min?
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    What are the torque and power calculations for a belt drive system?

    (i) To find linear speed in (m/s) v= RxW V=0.25x(300x(2pi/60)) v=0.25x31.4159 v=7.85m/s is that corect now? i don't get you on the rotational speed of pully B. if i get the rotational speed of the pully B, i will be able to have the correct value for Wb yeah?
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    What are the torque and power calculations for a belt drive system?

    Homework Statement (b) Fig. Q.6 shows a belt drive system where pulley A (diameter 0.5 m) is transmitting power to pulley B (diameter 0.25 m), mounted on a parallel rotating shaft. The tight and slack-side tensions of the belt are 500 N and 200 N respectively, and pulley A rotates at 300...
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    Distance travelled during acceleration.

    if the constant velocity is, as given 3m/s. why do they ask me to find the constant velocity?
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    Distance travelled during acceleration.

    Is the Distance traveled during acceleration correct? The constant velocity come from the second part of question (iii). Question: (iii)Determine The work done during acceleration and the constant velocity. Work done during acceleration W=FxD w= 36x18 w= 648 joules now how to find the...
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    Distance travelled during acceleration.

    second part of the question.
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    Distance travelled during acceleration.

    my bad s= 1/2(u+v)t s= 1/2(0+3)12 s= 1/2(3)12 s= 1.5(12) s= 18m Work done during acceleration and constant velocity W=FxD w= 36x18 w= 648 joules now how to find the constant velocity? is it c.v => (Mass x Tractive resistance rate) c.v= 80x0.2...
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    Distance travelled during acceleration.

    Homework Statement A cyclist accelerates from rest to a velocity of 3 m/s in 12 seconds, continues at this speed for one minute and then freewheels to stop. If the total mass of cyclist and cycle is 80 kg, and the tractive resistance rate may be assumed constant at 0.2 N/kg., Homework...
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    Determine kinetic energy gained by the mass during the acceleration

    Yeah i do understand what you mean. there come the problem, i don't know what equation i have to use. as i said i never done phisics befor
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