What is the kinetic energy of a falling rock?

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The Futur
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Homework Statement


b) A person standing on the edge of a 100 m high cliff drops a 0.5 kg stone vertically downwards. Determine the final velocity of the stone after falling 100m, and its kinetic energy.


Homework Equations


Final velocity
v = √(2gx)

The Attempt at a Solution



final velocity

v = √(2gx)
v = √(2(0.5x9.8)100)
v= 31.3m/s
is that correct?

how do i calculate the kinetic energy?
 
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The Futur said:
how do i calculate the kinetic energy?

Are you familiar with conservation of energy or the kinetic energy formula?
 
Last edited:
The Futur said:

Homework Statement


b) A person standing on the edge of a 100 m high cliff drops a 0.5 kg stone vertically downwards. Determine the final velocity of the stone after falling 100m, and its kinetic energy.


Homework Equations


Final velocity
v = √(2gx)

The Attempt at a Solution



final velocity

v = √(2gx)
v = √(2(0.5x9.8)100)
v= 31.3m/s
is that correct?

how do i calculate the kinetic energy?

The velocity is wrong. You don't use the mass to calculate it (see your formula).
The mass is used to calculate the kinetic energy.
 
so it will be

v = √(2gx)
v = √(2(9.8)100)
v= 44.27m/s ?

and no i don't know how to calculate the second part