Thanks for the help! Hoewever I am still having problems.
I want to make a proof by contradiction if log2(i) is irrational so that is why I start with a false assumption. I now made a new proof but I still do not get it:
log2(i) = m/n
ln(i)/ln(2) = m/n
ln(i) = ln(2)*m/n
e^(ln(2)*m/n) = i...
m and n are integers.
log2(i) = m/n
2^(m/n) = i
2^m = i^n
2^0 = i^4 = 1
so that means that log2(i) is rational because there are integers n and m so that log2(i) = m/n , they are m=0 and n=4.
But what I do get about this proof is that it seems to imply that log2(i) = 0/4 = 0 while google says...
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