Hmmm... I've been searching, and I found the formula
Q= 3/2 nRdT
Which gives me 1.5*5.5*8.31*280= 19196 Joules, which my textbook says is the correct answer.
Where did the 3/2 come from?
And in this problem, since it's adiabatic, it does not exchange heat, so if the temperature is going to go down, it must do positive work. I understand this.
I just don't understand how to apply this stuff about Cv and Cp. I am at a loss for what I should do mathematically and what all...
I see now that I was wrong to assume pressure is constant, but I'm afraid I'm still a little lost with the symbols and stuff.
What does PV^gamma mean? Is gamma an exponent? And if so, do I need to figure out what both P and V are on their own?
And what constant do they equal? My...
Homework Statement
During an adiabatic process, the temperature of 5.50 moles of a monatomic idea gas drops from 495 C to 215 C. For this gas, find (a) the work it does, (b) the heat it exchanges with its surroundings, and (c) the change in its internal energy
Homework Equations
I know...
so do I use the equation twice?
101.3 kPa = Pressure + (.5*1.29*53*53)
Pressure = 99488 Pascals
and then plug that in using water's density as rho the next time?
for a) i got the radius of straw r=.003 m
area and 1.5 L is .0015 m^3. Divide cubic meters by area of straw, and got 53.1 m/s
But for part b) How do you use Bernoulli's eqn? Do you assume the pressure at the top of the straw is appoxamately zero, since the air is being blown off?