Recent content by think4432
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Engineering Im having trouble analyzing this circuit
Also the leg is grounded to obtain electrical voltage?A small voltage is set up across the electrodes by the hearbeat/pulse . This voltage is sensed by the sensor/electrode and is fed to the input of the amplifier. [From a little more research] How does high pass and low pass filters play a...- think4432
- Post #7
- Forum: Engineering and Comp Sci Homework Help
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Engineering Im having trouble analyzing this circuit
Is this because if we did not do this, the circuit would produce a lot of leakage voltage?- think4432
- Post #6
- Forum: Engineering and Comp Sci Homework Help
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Engineering Im having trouble analyzing this circuit
I understand the Driven Right Leg circuit thanks to your explaining to an extent, but why is the requirement of resistors in the places that they are placed necessary? And what values of these resistors would be suitable? High values for some? Low for others? I am not fully understanding how...- think4432
- Post #5
- Forum: Engineering and Comp Sci Homework Help
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Engineering Im having trouble analyzing this circuit
I'm looking at this ECG circuit in particular and I am having trouble analyzing it... The ECG circuit and the driven right leg circuit to cancel out the noise. I am a little bit confused on what exactly the r1, the op amp and r2 do... And the values that are generally given to build...- think4432
- Thread
- Circuit
- Replies: 7
- Forum: Engineering and Comp Sci Homework Help
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Advanced Engineering Mathematics: Euler Method
I don't think we're learning about Taylor series, but I just don't understand how we would solve the DE... I can probably apply to Euler's method after solving it...- think4432
- Post #3
- Forum: Calculus and Beyond Homework Help
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Advanced Engineering Mathematics: Euler Method
Do 10 steps. Solve the problem exactly. Compute the error (Show all details). The problems says do 10 steps, but 3-4 steps will suffice! Problem: y(prime) = (y-x)^2 y(0) = 0 h = 0.1 I don't understand how to get the exact solution and what to do from there! I know that, f(x,y) =...- think4432
- Thread
- advanced Engineering Euler Euler method Mathematics Method
- Replies: 3
- Forum: Calculus and Beyond Homework Help
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Calculators Is there a program for TI-84 that can solve integrals without showing steps?
Thank you for the reply! What does the fnInt function do? And where can I find it?- think4432
- Post #4
- Forum: Computing and Technology
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Calculators Is there a program for TI-84 that can solve integrals without showing steps?
Any downloads would work too?- think4432
- Post #2
- Forum: Computing and Technology
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Calculators Is there a program for TI-84 that can solve integrals without showing steps?
I don't know if this is the right place to post a question like this...but help? Does anyone know of a good program that can be downloaded to a ti84 that can solve integrals? It doesn't have to show the steps...just an answer [that you could check while doing homework...if you don't have...- think4432
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- Integral Program Ti-84
- Replies: 4
- Forum: Computing and Technology
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Work and Fluid Force: Calculus II
Ok! Thank you very much. Happy Fathers Day to you! Hope you enjoy the rest of your day! Thanks so much for your help though. You are great.- think4432
- Post #78
- Forum: Calculus and Beyond Homework Help
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Work and Fluid Force: Calculus II
Yes. Sorry I just had a typo A = -5 and B = -1 When you evaluate -5 [lower limit] you get -1225/24 And when you evaluate the -1 [upper limit] you get 7/24 So 7/24 - (-1225/24) You get 154/3 times the weight density. Which is 154/3 * 62.4 = 3203.2 ?- think4432
- Post #76
- Forum: Calculus and Beyond Homework Help
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Work and Fluid Force: Calculus II
I still get 154/3(62.4) And then when I multiply that out I get 3203.2 ft(lb)- think4432
- Post #74
- Forum: Calculus and Beyond Homework Help
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Work and Fluid Force: Calculus II
there's no pi in this problem, correct? So the problem is just the limits a = -1 and b = -5 and integrating (7/24)(y^2) + (2y+3) With the water density of 62.4 lb/ft^3 outside of the integral as a constant? Correct?- think4432
- Post #73
- Forum: Calculus and Beyond Homework Help
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Work and Fluid Force: Calculus II
Oh! Oh! Oh! Sorry! Sorry! I was looking at the other thread and got mixed up! The limits are -5 to -1! -154/3? I did something wrong?- think4432
- Post #71
- Forum: Calculus and Beyond Homework Help
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Work and Fluid Force: Calculus II
Yes. Thats where I got the units from.- think4432
- Post #70
- Forum: Calculus and Beyond Homework Help