Recent content by Thiru07

  1. Thiru07

    Doubt in an inequality problem

    In that case , we will keep y < -2 and ignore y < 3. I think I got it. We have to ignore y+2 <= 0 and y-3 >=0 as is not possible and keep Thanks PeroK :)
  2. Thiru07

    Doubt in an inequality problem

    Homework Statement Given : (y+2)(y-3) <= 0Homework EquationsThe Attempt at a Solution Now, I have y-3 <= 0 or y+2 <= 0 Hence, y <= 3 or y <= -2 But how is correct? I think is wrong because y <= -2. Can someone please clarify?
  3. Thiru07

    How do I approach this problem? (Cubes within a larger cube....)

    Thank you so much for your time and effort :smile:
  4. Thiru07

    How do I approach this problem? (Cubes within a larger cube....)

    How did you get 56? I got only 48 from counting all these 6 surface cubes which are completely covered with number 9. By the way , Attached is the given solution which I did not understand. Can you please tell if it makes any sense?
  5. Thiru07

    How do I approach this problem? (Cubes within a larger cube....)

    Previously, I thought peeling off as peeling off all the six surfaces, which reduces the 8x8x8 cube to 6x6x6 cube. When you say peeling off a layer you mean peeling off just one surface right? i.e After peeling off , you get a 8x8x7 cube. Please correct me if I'm wrong.
  6. Thiru07

    How do I approach this problem? (Cubes within a larger cube....)

    Okay, if I peel off twice , I will get a 4x4x4 cube with number 27(multiple of 3) on all 6 faces. Why do I think that the total number of cubes along all six faces of this 4x4x4 cube is the answer which is 48 and not 296? Why I'm wrong?
  7. Thiru07

    How do I approach this problem? (Cubes within a larger cube....)

    Number of cubes bearing the numbers which are multiple of three is 296 What I'm getting is (4*8)+(4*8)+(4*8) = 96 I missed a lot of cubes. But I don't know which cubes I skipped. are 1,4,9 and 16 the only numbers smaller cubes can bear?
  8. Thiru07

    How do I approach this problem? (Cubes within a larger cube....)

    I have 3 more questions from the same problem. 1) Find the number of cubes bearing the numbers which are multiple of three. 2) Find the sum of numbers on all the smaller cubes on the surface of the larger cube. 3) Find the number of cubes bearing the number 8 on them. I...
  9. Thiru07

    How do I approach this problem? (Cubes within a larger cube....)

    I'm getting 4*(1+4+9+16) = 120 as the sum of the numbers on the cubes along the two body diagonals of the largest cube. What am I doing wrong?
  10. Thiru07

    How do I approach this problem? (Cubes within a larger cube....)

    Cubes(1cm x 1cm x 1cm) numbered 4,9 and 16 are present inside the largest cube(8cm x 8cm x 8cm) and not on the surface as it appears above in the 2D image right? If that's the case, then these cubes numbered 4,9 and 16 are invisible right? Only cubes numbered 1 are visible i.e all the six...
  11. Thiru07

    How do I approach this problem? (Cubes within a larger cube....)

    How did you get all those perfect squares of odd numbers? Can you please explain your 2D structure? What do you mean by ?
  12. Thiru07

    How do I approach this problem? (Cubes within a larger cube....)

    I went through it's solution , but I hardly understood anything.
  13. Thiru07

    How do I approach this problem? (Cubes within a larger cube....)

    Homework Statement A cube of 8cm x 8cm x 8cm is divided into smaller cubes of 1cm x 1cm x 1cm and all the smaller cubes are numbered and arranged to form the larger cube. The smaller cubes are numbered such that the number on the cube represents the smallest volume enclosed by extending the...
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