In that case , we will keep y < -2 and ignore y < 3.
I think I got it. We have to ignore y+2 <= 0 and y-3 >=0 as
is not possible and keep
Thanks PeroK :)
Homework Statement
Given : (y+2)(y-3) <= 0Homework EquationsThe Attempt at a Solution
Now, I have y-3 <= 0 or y+2 <= 0
Hence, y <= 3 or y <= -2
But how
is correct?
I think
is wrong because y <= -2.
Can someone please clarify?
How did you get 56?
I got only 48 from counting all these 6 surface cubes which are completely covered with number 9.
By the way , Attached is the given solution which I did not understand.
Can you please tell if it makes any sense?
Previously, I thought peeling off as peeling off all the six surfaces, which reduces the 8x8x8 cube to 6x6x6 cube.
When you say peeling off a layer you mean peeling off just one surface right? i.e After peeling off , you get a 8x8x7 cube. Please correct me if I'm wrong.
Okay, if I peel off twice , I will get a 4x4x4 cube with number 27(multiple of 3) on all 6 faces.
Why do I think that the total number of cubes along all six faces of this 4x4x4 cube is the answer which is 48 and not 296?
Why I'm wrong?
Number of cubes bearing the numbers which are multiple of three is 296
What I'm getting is (4*8)+(4*8)+(4*8) = 96
I missed a lot of cubes. But I don't know which cubes I skipped.
are 1,4,9 and 16 the only numbers smaller cubes can bear?
I have 3 more questions from the same problem.
1) Find the number of cubes bearing the numbers which are multiple of three.
2) Find the sum of numbers on all the smaller cubes on the surface of the larger cube.
3) Find the number of cubes bearing the number 8 on them.
I...
Cubes(1cm x 1cm x 1cm) numbered 4,9 and 16 are present inside the largest cube(8cm x 8cm x 8cm) and not on the surface as it appears above in the 2D image right?
If that's the case, then these cubes numbered 4,9 and 16 are invisible right?
Only cubes numbered 1 are visible i.e all the six...
Homework Statement
A cube of 8cm x 8cm x 8cm is divided into smaller cubes of 1cm x 1cm x 1cm and all the smaller cubes are numbered and arranged to form the larger cube. The smaller cubes are numbered such that the number on the cube represents the smallest volume enclosed by extending the...