Recent content by thornear

Whatever I did worked. I checked w/ someone else who did it also and they had the same answer. Thanks for your help.

OK, so I took the points A(12,0,0), B(0,16,0), and C(0,0,9) and found vectors AB = -12i + 16j + 0k and BC = 0i -16j + 9k. I crossed those vectors and came up w/ 144i + 108j + 192 k then by choosing point A, found the eq. for the plane, 144x + 108y + 192z = 1728. I substituted the coordinates...

I want to say that the vector is perpendicular to the plane would I don't think that's necessarily true. If it were just a point, then the shortest distance would be a perpendicular line from the point to the plane. I know the vector has to have equal angles w/ the x, y, and z axes but I can't...

OK, I understand the 3-D bit. But let me see if I follow you, The sum of the squares, x2 + x2 + x2 = 3x2 and the square of the displacement from the origin, 602 = 3600 Now, 3600 = 3x2 \frac{3600}{3} = x2 x = 34.64 But where does the coordinates of the plane come in?

Homework Statement The vector from the origin, O, to point P has magnitude 60 m and has equal direction angles with the x, y, and z axes. Find the shortest distance from point P to the plane containing points A, B, and C. A (12,0,0) B (0,16,0) C (0,0,9) Homework Equations N/A The Attempt...

Making g negative makes sense to me but it begins to produce negative velocities. Also I made a mistake in the above post, t = 0... V = 20 + [9.81 - (.25/80)(0)2] *1 = 29.81m/s t= 1...V = 29.81 + [9.81 - (.25/80)2]*1 = 36.51m/s t =2....V=36.51 + [9.81-(.25/80)2]*1 = 42.15 m/s ...so on...

Homework Statement For the second order drag model (Eq. 1.8), compute the velocity of a free-falling parachutist using Euler's method for the case where, m = 80 kg Cd = .25 kg/m Perform the calculation from t = 0 to 20 with a step size of 1 s. Use an initial condition that the parachutist...