Recent content by thst1003

Initially a 1.52 µF capacitor and a 2.63 µF capacitor are connected in parallel, with 9.80 V across their plates. The two capacitors are not connected to anything else. The connecting wires are then reversed on the terminals of one capacitor, so that the positive plate of each capacitor is...

Thanks! I actually was using my calculator in the incorrect mode. I figure it out. I really appreciate it.

An electron is near a positive ion of charge +9e and a negative ion of charge −8e (see the figure below). (Take a = 5.23 µm, b = 4.28 µm, and θ = 54.9°.) (a) Find the magnitude and direction of the resultant force on the electron. (Let right be the +x-direction. Measure the angle...

[b]1. Hanging from threads are two charged balls made of pith (a very light, spongy material that comes from inside the stems of certain plants). The balls each have a mass of 0.100 g and a charge of the same magnitude q and are attracted toward each other, as shown in the figure below...

Anyone?? I can't figure it out!

Suppose that you were to apply just enough mass so that four "loops" (harmonics) are visible on a standing wave. If the mass density of the string were to double, how many loops (harmonics) if any would be visible? What about if the mass density were to quadruple? Explain. This was a lab...

What exactly do you divide? Is it Electrical force/Gravitational force using 1.6e-19 C for the electron and the electron? So it would be k(q)(q) / G(m1)(m2) ?

I changed the question. I have encountered it.

An electron is near a positive ion of charge +9e and a negative ion of charge −8e (see the figure below). (Take a = 5.23 µm, b = 4.28 µm, and θ = 54.9°.) (a) Find the magnitude and direction of the resultant force on the electron. (Let right be the +x-direction. Measure the angle...

Find the ratio of the magnitudes of the electrical and the gravitational forces acting between a proton and an electron separated by an arbitrary distance d. F= k(q)(q')/r^2 and The q's are in an absolute value sign. How do I find the ratio? Is it as simply as dividing it out?

For this problem, the wisest way to go about it is the way that you said. Think about it this way. If it is independent and the hacker may or may not retry the same password. One must compute the odds that the hacker will get it right on his first try. That means 1/(26*26). Once we get this we...

Perhaps you need to calculate something dealing with the speed of sound... I can't remember this stuff. It was a while ago.

Homework Statement Three charges, q1 = +2.10 10-9 C, q2 = -3.09 10-9 C, and q3 = +1.08 10-9 C, are located on the x-axis at x1 = 0, x2 = 10.0 cm and x3 = 20.0 cm. Find the resultant force on q3. I am unsure of how to even attempt this problem...

You are right. I overlooked that. I am betting that your answer is correct. The difference could possibly attributed to the fact that the speed of sound can vary. Sorry about my incorrect answer.

You had everything right. Except the sign on the bottom. Given the fact that the source is moving TOWARDS the observer the sign on the bottom should be negative whereas you have it positive. That should make the difference...