@haruspex, larger than expected, I see my error converting at the start and will arrange the units accordingly in my answer. Appreciate the assistance.
Apologies the subscript was an error when I read the original equation, it was actually to the base of that figure. I've corrected in the attached and included the relevant units within the equation.
Latex is something I will certainly need to learn.
Homework Statement
(I) An experiment to determine ceramic particle sizes showed that the rate of descent when suspended in a fluid ranged from 1.2 × 10–6 m s–1 to 5 × 10–6 m s–1. The density of the material was 3800 kg m–3 and the density and viscosity of the fluid at room temperature were...
There is no significance in the nested brackets, they only appear when copying from MS Word MathScript to the PhysicsForum.
The 18η is represented in correctly in the above as well due to this conversion.
v = d^2 (ps - p1) g / 18η
This is the relevant equation.
Yes, the first part of the...
Calculate the range of sizes of the particles.
ν= velocity of decent
d = diameter
ps = density
η = viscosity
P1 = density
v= (d^2 (p_s-p_1 )g)/〖18〗_η
Rearrange for the diameter.
v= (d^2 (p_s-p_1 )g)/〖18〗_η
〖18〗_η v= d^2 (p_s-p_1 )g
(〖18〗_η v)/(p_s-p_1 )g= d^2
√((〖18〗_η...
Sorry I'm not following. The notes of this module have led to a great amount of confusion.
1/U(0.021) = 1/4.2*(0.020) + 1/15.4*(0.022) + 0.112/0.021
For the above, would we not transpose to remove U from the base.
Attaining: U = 1/(0.021) - 1/4.2*(0.020) + 1/15.4*(0.022) + 0.112/0.021