Recent content by Tiberious

  1. T

    Determining ceramic particle sizes suspended in a fluid

    @haruspex, larger than expected, I see my error converting at the start and will arrange the units accordingly in my answer. Appreciate the assistance.
  2. T

    Determining ceramic particle sizes suspended in a fluid

    Apologies the subscript was an error when I read the original equation, it was actually to the base of that figure. I've corrected in the attached and included the relevant units within the equation. Latex is something I will certainly need to learn.
  3. T

    Determining ceramic particle sizes suspended in a fluid

    Hiya all really appreciate the feedback, I've added some units to the equation. Does the above seem accurate ? Any obvious omissions ?
  4. T

    Determining ceramic particle sizes suspended in a fluid

    As the question was in microns and the material in milli, I've converted to milli. The above should read mm. Apologies for that.
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    Determining ceramic particle sizes suspended in a fluid

    Thank-you, any ideas as towards the rearrangement of the formula ?
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    Determining ceramic particle sizes suspended in a fluid

    Homework Statement (I) An experiment to determine ceramic particle sizes showed that the rate of descent when suspended in a fluid ranged from 1.2 × 10–6 m s–1 to 5 × 10–6 m s–1. 
The density of the material was 3800 kg m–3 and the density and viscosity of the fluid at room temperature were...
  7. T

    Calculate the range of sizes of the particles

    There is no significance in the nested brackets, they only appear when copying from MS Word MathScript to the PhysicsForum. The 18η is represented in correctly in the above as well due to this conversion. v = d^2 (ps - p1) g / 18η This is the relevant equation. Yes, the first part of the...
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    Calculate the range of sizes of the particles

    Calculate the range of sizes of the particles. 
 ν= velocity of decent d = diameter ps = density η = viscosity P1 = density v= (d^2 (p_s-p_1 )g)/〖18〗_η Rearrange for the diameter. v= (d^2 (p_s-p_1 )g)/〖18〗_η 〖18〗_η v= d^2 (p_s-p_1 )g (〖18〗_η v)/(p_s-p_1 )g= d^2 √((〖18〗_η...
  9. T

    A heat exchanger is to be used to heat a process liquid with....

    Apologies for the slow reply, I've been a little busy of late. Please see the below.
  10. T

    A heat exchanger is to be used to heat a process liquid with....

    So far I've got this. Then do we divided by D on both sides ? Removing D on the LHS. Does each term on the base of the RHS get divided by D ?
  11. T

    A heat exchanger is to be used to heat a process liquid with....

    As we are dividing my D in the previous we should multiply when transposed. I assume this is correct.
  12. T

    A heat exchanger is to be used to heat a process liquid with....

    Does the transposition look anything like the below.
  13. T

    A heat exchanger is to be used to heat a process liquid with....

    Sorry I'm not following. The notes of this module have led to a great amount of confusion. 1/U(0.021) = 1/4.2*(0.020) + 1/15.4*(0.022) + 0.112/0.021 For the above, would we not transpose to remove U from the base. Attaining: U = 1/(0.021) - 1/4.2*(0.020) + 1/15.4*(0.022) + 0.112/0.021
  14. T

    A heat exchanger is to be used to heat a process liquid with....

    Hey, went back to my lecturer with the below and it seems Ra is correct but not U. Can you check if I have followed your advise correctly.
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