Recent content by Tiberious

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    Determining ceramic particle sizes suspended in a fluid

    @haruspex, larger than expected, I see my error converting at the start and will arrange the units accordingly in my answer. Appreciate the assistance.
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    Determining ceramic particle sizes suspended in a fluid

    Apologies the subscript was an error when I read the original equation, it was actually to the base of that figure. I've corrected in the attached and included the relevant units within the equation. Latex is something I will certainly need to learn.
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    Determining ceramic particle sizes suspended in a fluid

    Hiya all really appreciate the feedback, I've added some units to the equation. Does the above seem accurate ? Any obvious omissions ?
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    Determining ceramic particle sizes suspended in a fluid

    As the question was in microns and the material in milli, I've converted to milli. The above should read mm. Apologies for that.
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    Determining ceramic particle sizes suspended in a fluid

    Thank-you, any ideas as towards the rearrangement of the formula ?
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    Determining ceramic particle sizes suspended in a fluid

    Homework Statement (I) An experiment to determine ceramic particle sizes showed that the rate of descent when suspended in a fluid ranged from 1.2 × 10–6 m s–1 to 5 × 10–6 m s–1. 
The density of the material was 3800 kg m–3 and the density and viscosity of the fluid at room temperature were...
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    Calculate the range of sizes of the particles

    There is no significance in the nested brackets, they only appear when copying from MS Word MathScript to the PhysicsForum. The 18η is represented in correctly in the above as well due to this conversion. v = d^2 (ps - p1) g / 18η This is the relevant equation. Yes, the first part of the...
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    Calculate the range of sizes of the particles

    Calculate the range of sizes of the particles. 
 ν= velocity of decent d = diameter ps = density η = viscosity P1 = density v= (d^2 (p_s-p_1 )g)/〖18〗_η Rearrange for the diameter. v= (d^2 (p_s-p_1 )g)/〖18〗_η 〖18〗_η v= d^2 (p_s-p_1 )g (〖18〗_η v)/(p_s-p_1 )g= d^2 √((〖18〗_η...
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    Overall heat transfer coefficient with fouling factor in tubes

    Apologies for the slow reply, I've been a little busy of late. Please see the below.
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    Overall heat transfer coefficient with fouling factor in tubes

    So far I've got this. Then do we divided by D on both sides ? Removing D on the LHS. Does each term on the base of the RHS get divided by D ?
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    Overall heat transfer coefficient with fouling factor in tubes

    As we are dividing my D in the previous we should multiply when transposed. I assume this is correct.
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    Overall heat transfer coefficient with fouling factor in tubes

    Does the transposition look anything like the below.
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    Overall heat transfer coefficient with fouling factor in tubes

    Sorry I'm not following. The notes of this module have led to a great amount of confusion. 1/U(0.021) = 1/4.2*(0.020) + 1/15.4*(0.022) + 0.112/0.021 For the above, would we not transpose to remove U from the base. Attaining: U = 1/(0.021) - 1/4.2*(0.020) + 1/15.4*(0.022) + 0.112/0.021
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    Overall heat transfer coefficient with fouling factor in tubes

    Hey, went back to my lecturer with the below and it seems Ra is correct but not U. Can you check if I have followed your advise correctly.