Calculate the range of sizes of the particles

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Homework Help Overview

The discussion revolves around calculating the range of sizes of particles based on their rate of descent in a fluid, utilizing the equation that relates velocity, diameter, density, and viscosity. Participants are examining the rearrangement of this equation to isolate the diameter.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to rearrange the equation for diameter and are questioning the correctness of their manipulations. There are inquiries about the significance of notation and the definitions of variables involved, particularly regarding the densities represented.

Discussion Status

Some participants have provided feedback on the rearrangement attempts, indicating that the manipulations appear correct. There is also mention of the clarity of notation and suggestions for using LaTeX for better readability. The original poster and others are exploring the implications of the equation and its components without reaching a consensus on the final outcome.

Contextual Notes

Participants are working with specific values for densities and viscosity, as well as a defined range for the rate of descent, which are critical for the calculations but are not fully resolved in the discussion.

Tiberious
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Calculate the range of sizes of the particles. 


ν= velocity of decent
d = diameter
ps = density
η = viscosity
P1 = density

v= (d^2 (p_s-p_1 )g)/〖18〗_η

Rearrange for the diameter.

v= (d^2 (p_s-p_1 )g)/〖18〗_η

〖18〗_η v= d^2 (p_s-p_1 )g

(〖18〗_η v)/(p_s-p_1 )g= d^2

√((〖18〗_η v)/(p_s-p_1 )g)= d

Is the above rearrangement correct ? If not, are there any helpful sites / posts that you are aware of to solve rearranging equation problems ?
 
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Tiberious said:
Calculate the range of sizes of the particles. 


ν= velocity of decent
d = diameter
ps = density
η = viscosity
P1 = density

v= (d^2 (p_s-p_1 )g)/〖18〗_η
I have a few questions about this equation.
What is the significance of the double brackets on 18: i.e., 〖18〗?
What does this part mean? 〖18〗_η
What densities do ps and P1 represent? Presumably they are the same as p_s and p_1 in your equation.
Tiberious said:
Rearrange for the diameter.

v= (d^2 (p_s-p_1 )g)/〖18〗_η

〖18〗_η v= d^2 (p_s-p_1 )g

(〖18〗_η v)/(p_s-p_1 )g= d^2

√((〖18〗_η v)/(p_s-p_1 )g)= d

Is the above rearrangement correct ? If not, are there any helpful sites / posts that you are aware of to solve rearranging equation problems ?
 
There is no significance in the nested brackets, they only appear when copying from MS Word MathScript to the PhysicsForum.

The 18η is represented in correctly in the above as well due to this conversion.

v = d^2 (ps - p1) g / 18η

This is the relevant equation.

Yes, the first part of the question is as follows.

"An experiment to determine ceramic particle sizes showed that the rate of descent when suspended in a fluid ranged from 1.2× 10–6 m s–1 to 5× 10–6 m s–1. 


The density of the material was 3800 kg m–3 and the density and viscosity of the fluid at room temperature were 1632 kg m–3 and 0.00972 Pas respectively. Calculate the range of sizes of the particles. "
 
Tiberious said:
√((〖18〗_η v)/(p_s-p_1 )g)= d
Is the above rearrangement correct ?
Looks fine to me, but is somewhat hard to read.. Using LaTeX (see our tutorial here - https://www.physicsforums.com/help/latexhelp/), it would be $$d = \pm \sqrt{\frac{18\eta v}{(p_s - p_1)q}}$$.
If this is a problem from physics, you probably don't need to be concerned about the negative square root.
Tiberious said:
If not, are there any helpful sites / posts that you are aware of to solve rearranging equation problems ?
Regarding helpful sites: For this problem, other sites are not needed. Solving for d here is basically two steps:
  1. Multiply both sides of the equation by ##\frac{18 \eta}{(p_s - p_1)g}##
  2. Take the square root of both sides
 
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