Recent content by tj Cho
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The quarter disk in the first quadrant bounded by x^2+y^2=4
Find the coordinate of center of mass. Given: The quarter disk in the first quadrant bounded by x^2+y^2=4 I tried to solve this problem but can't figure out how to do it. so y integration limit is: 0 <= y <= sqrt(4-x^2)) x limit of integration: 0 <= x <= 2 and then after the dy integral I...- tj Cho
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- Bounded Calculus Center of mass Disk Double integral
- Replies: 2
- Forum: Calculus and Beyond Homework Help
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Lab experiment on moment of inertia dynamic
The Angular velocity when the hanging mass hit the floor, I attached a better sketch- tj Cho
- Post #7
- Forum: Introductory Physics Homework Help
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Lab experiment on moment of inertia dynamic
This equation is given in the lab manual to find I_cyl (I mis-typed in the post sorry) Icyl = (2hgM_cylinder) * (1/(W_withcylinder)^2 - 1/(W_nocylinder)^2) where h is the height = 0.9 m (height from hanging mass to the floor) M_cylinder mass of the cylinders = 0.0757 kg W_withcylinder and...- tj Cho
- Post #5
- Forum: Introductory Physics Homework Help
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Lab experiment on moment of inertia dynamic
I_Cyl is I_sys - I_rod. I think by the moment of inertia of the cylinder they mean the moment of inertia of the two masses. Can you please look at the excel sheet at column J that is my partner data, I don't know where he got that equation to calculate the I_cyl- tj Cho
- Post #3
- Forum: Introductory Physics Homework Help
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Lab experiment on moment of inertia dynamic
Homework Statement That is the set up for experiment, and I attached the data I found in the lab. The lab given me the equation to find the moment of inertia of the cylinder Homework Equations Icyl = (2hgM_cylinder) * (1/(W_withcylinder)^2 - 1/(W_nocylinder)^2) The height is 0.9m The Attempt at...- tj Cho
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- Dynamic Experiment Inertia Lab Moment Moment of inertia
- Replies: 7
- Forum: Introductory Physics Homework Help