Is the way I worked the problem out correct? I just need to convert the 217.6 watts to hp? I have had trouble solving this problem. It would be nice to know if this thinking is correct.
Ok-so hopefully this is it:
W=(mass of skier*acceleration)(change in distance)(cos29.9)
W=(132.43)(59.8)(cos29.9)=6865.23.
Then take that value and divide by the time which is 31.55 seconds.
Which equals 217.6 hp
Ok so the F in the problem is 9.8m/s^2. I would use cos0. However, the change in distance is unknown. Using the formula d=time * speed, I found it to be 8.75m. So, now would I use the work formula with the numbers (9.8m/s^2)(8.75m)(cos0). Which equals 85.57J. After I find that I would divide...
Homework Statement
A skier of mass 69.7 kg is pulled up a slope by a motor-driven cable.
(a) How much work is required to pull him a distance of 59.8 m up a 29.9° slope (assumed frictionless) at a constant speed of 1.90 m/s?
(b) A motor of what power is required to perform this task?
hp...
The normal force for this problem is W=F*displacement*cos90. W=366.5*5.00*0. Which equals zero. Then, I am not sure what to do to find the increase in internal energy and the total change in the block's kinetic energy. That is where my confusion comes to play.
Homework Statement
A 14.0 kg block is dragged over a rough, horizontal surface by a 78.0 N force acting at 20.0° above the horizontal. The block is displaced 5.00 m, and the coefficient of kinetic friction is 0.300.
(a) What is increase in internal energy of the block-surface system due to...
I could not copy and past the pic...it wouldn't let me paste it on here. It's pretty much a verticle rod with a string coming from the top and the bottom corners to form a triangle. That's the best way I know how to depict it. Sorry