I think I understand now.. I don't have time to type what I'm thinking atm, but I'll be back later to see if you agree with my newfound reasoning.
Posting this because I don't want anyone to spend time explaining to me when I've figured it out :)
I don't think I did?
If you set up the area around the pump as the control volume, with the area of pipe being equal before and after, whatever energy/second is transferred to the flow, will be in the form of Pressure * flow rate. Kinetic energy, internal energy and potential energy will be the...
For a scenario w/o a pump, such as an elevated reservoir or something, the flow rate would be determined by the area at the outlet and the pressure difference. For a pump scenario on the other hand, the flow rate is determined by the pump, no?
When I do calculations for drill strings, their...
I made up the numbers. With a pump, you can get pretty much w/e Pressure & speed situation inside the pipe you'd like.. no?
For the numbers I have, we can make up that upstream from where we are looking there is a 3 piston pump. The pistons have an area equal to A1 = π m2. To get P1 = 500 kPa...
Homework Statement
Water is flowing through a nozzle with entrance data:
P1 = 500 kPa
V1 = 10 m/s
A1 = π m2
ρ = 1000 kg/m3.
Exit data:
P2 = atmospheric pressure, assume 100 kPa to make numbers easy
V2 = ?
A2 = π (0.5)2
ρ = 1000 kg/m3
With what speed does the water exit the...
Assuming Patm is correct to use, for a horisontal pipe with an opening to the atmosphere we would have: V12/2 + P1/ρ = V22/2 + Patm/ρ
where 1 = somewhere downstream and 2 = directly outside the pipe
If we assume the pipe has a constant area, the continuity equation gives us V1 = V2, leaving...
Torricelli's theorem relates the speed of a fluid exiting an opening in a reservoir to the height of the opening relative to the top of the reservoir... V=√2gh https://en.wikipedia.org/wiki/Torricelli%27s_law
As seen in the wiki-link provided, the equation is essentially a Bernoulli's...
My prof. made me question what magnitude of acceleration is.. Is it acceleration without direction, i.e -6 m/s/s becomes 6 m/s/s or is it ΔV(speed)/Δt (Sorta like magnitude of acceleration is to acceleration what speed is to velocity)?
aah I get it!
the sum of F on M1 is 9.8N. Divided by 3kg = 3.267 m/s2.
Sum of F on whole system = force by rope - friction
(7kg * 3.267 m/s2) +13.72 = force by rope
36.589 = force by rope
Thank you!
I get:
max tension = F2 = 23.52 N
Friction F1 = μk * n = 0.2 * 9.8 *7 = 13.72
tension on string = sum of forces on string = F2 - F1 = 37.24 N
The answer is supposed to be 36.6 N. What did I do wrong?
I really appreciate the help!
Homework Statement
There are two blocks stacked on top of each other. M2 is on top of M1. M1 = 3 kg. m2 = 4 kg. μs between the two boxes = 0.6. μk between m2 and the floor = 0.2.
Using a rope, we exert a force T on m2, dragging both boxes 5m. What is the maximum force we can exert on m2, if...