Recent content by Tomy World

Attached image shows how to get $$dE = -Tdx + E\frac{dx} {x}$$ This is interesting. But I'm not sure how this approach helps in solving the problem ;-)

To solve this problem, these are the key equations to be resolved. $$\frac {dm} {dx} = \frac {M} {L} $$.... get m(x) $$T=ma ⇒ \frac {dT} {dx} = 0 = m \frac {da} {dx} + a \frac {dm} {dx} $$.... get a(x) $$a = \frac {dv} {dt} = \frac {dv} {dx} \frac {dx} {dt} = v \frac {dv} {dx} ⇒ a dx = v dv...

Haha, fair comment! Clear sign convention and learning the right methodology are more important than getting the right answer.

Hi, In your case, + or - π will give you the right answer ;)

Hi, everything you did was correct, except that m_A should be not included in this free body diagram analysis. Review this. That's causing error in your calculation.

The confusion is in the question itself. If gravity is 9.2 m/s^2 (as stated in the question), then satellite distance from earth center is 6580km (verify yourself!). And that distance should not be called altitude :-( If altitude is really 6580km, g is about 2.38 m/s^2.

YEs. When you plot s vs t2, it becomes a straight line equation.

In your experiment, s = (1/2)g t2 After your conversion and plot, your graph is similar to following equation. y = (1/2)g x .... general equation of a straight line. Slope is therefore (1/2)g, .... there's nothing wrong, right?

1) Correct 2) Wrong. Check yr answer again! 3) What are the generic rules for below: sin(π + θ) = ? cos(π + θ) = ? Apply above result to below to see relation with 1. Cy = C sin(ϒ) = C sin(π + δ) = ? Cx = C cos(ϒ) = C cos(π + δ) = ? 4) What are the generic rules for sin(2π + θ) = ? cos(2π +...

Exactly. I feel the question is incomplete. When I work on this question, I assume piston is not moved. If so, how would you expect the result? Kindly share.

There is no more conditions given to this question. I believed that additional mercury will compress the gas inside cylinder, therefore gas pressure increases. As a result, both mercury levels will increase. And the difference of the mercury levels is higher than 0.2m.

May be 'challenge' is a strong word. I don't mean that ;)